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A coil C of N turns is placed around a long solenoid S of radius R and n turns per unit length, as in Figure. (a) Show that the mutual inductance for the coil–solenoid combination is given by M=μ0πR2nN. (b) Explain why M does not depend on the shape, size, or possible lack of close packing of the coil.

Short Answer

Expert verified
  1. It is shown that the mutual inductance for the coil – solenoid combination isM=μ0πR2nN
  2. M does not depend on the shape, size or possible lack of close packing of the coil because the magnetic field of the solenoid is entirely contained within the cross-section of the coil.

Step by step solution

01

Given

  1. Number of turns in the coil are N.
  2. Number of turns in the solenoid are n.
  3. Radius of solenoid is R.
02

Understanding the concept

We have the relation between the mutual inductance and flux linked in the solenoid. We also have the formula for the flux linked in the solenoid. So, we can prove the required formula for M.

Formula:

Mutual inductance is given by,

M=NϕIϕ=μ0InA

03

(a) Show that the mutual inductance for the coil – solenoid combination is M=μ0πR2nN

We have mutual inductance given by,

M=NϕI

But,

ϕ=μ0InAM=Nμ0InAI

Here, the solenoid has cross – section as the circular cross – section.

A=πR2M=Nμ0InπR2I

04

Explain why M does not depend on the shape, size or possible lack of close packing of the coil.

We know that the magnetic field of the solenoid is entirely contained within the cross-section of the coil, which is given by,

ϕ=BA

The solenoid has cross – section as the circular cross – section.

A=πR2ϕ=BπR2

From this, we can say that, M does not depend upon the shape, size or possible lack of close packing of the coil.

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