Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Figure 13-22 shows three arrangements of the same identical particles, with three of them placed on a circle of radius 0.20mand the fourth one placed at the center of the circle. (a) Rank the arrangements according to the magnitude of the net gravitational force on the central particle due to the other three particles, greatest first. (b) Rank them according to the gravitational potential energy of the four-particle system, least negative first.

Short Answer

Expert verified
  1. The rank according to the net gravitational force on the central particle is c > b > a.
  2. The rank according to the gravitational potential energy on the central particle is a = b = c.

Step by step solution

01

Identification of the given data

The radius of the circle is, r = 0.20 m

02

Expression of the gravitational potential energy

The expression for the gravitational potential energy of the system of the particles is as follows,

U=GMmr

Here, G is the gravitational constant, M is the mass of the heavy body, m is the mass of the light body, and R is the distance between two bodies.

03

(a) Determination of the rank according to the net gravitational force on the central particle

The magnitude of the gravitational force in all three arrangements is the same because in all arrangements, the particles are identical and the distance of the particles on the circle from the particle at the center of the circle is the same. But, the directions of the forces are different.

Write expression for the gravitational force of attraction between two bodies.

F=GMmR2

Here, G is the gravitational constant, M is the mass of the heavy body, m is the mass of the light body, and R is the distance between two bodies.

In the first arrangement, the forces due to the upper and lower particles on the circle get canceled out and will be zero by considering the above equation.

So, the net force acting on the particle at the center is due to the third particle.

In the third arrangement, forces due to all three particles are parallel to each other. So, in this arrangement, the net force on the particle at the center will be the greatest as they add up by considering the above equation.

Thus, the rank according to the net gravitational force on the central particle is c > b > a.

04

(b) Determination of the rank according to the gravitational potential energy on the central particle

It is known that all arrangements of the particles are identical and the distance of the particles on the circle from the particle at the center of the circle is the same. So, the gravitational potential energy in all those arrangements will be the same by considering the equation of gravitational potential energy.

Thus, the rank according to the gravitational potential energy on the central particle is a = b = c.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A thin rod with massM=5.00kg M=is bent in a semicircle of radiusR=0.650m. (Fig. 13-56). (a) What is its gravitational force (both magnitude and direction on a particle with massm=3.0ร—10-3kgat P, the center of curvature? (b) What would be the force on the particle the rod were a complete circle?

Question: Four uniform spheres, with masses mA 40 kg ,mB = 35 kg , mC = 200 kg , and mD = 50 kg , have (x, y) coordinates of(0,50 cm), (0,0) ,(-80 cm,0) , and (40 cm,0) , respectively. In unit-vector notation, what is the net gravitational force on sphere Bdue to the other spheres?

We watch two identical astronomical bodies Aand B, each of mass m, fall toward each other from rest because of the gravitational force on each from the other. Their initial center-to-center separation isRi. Assume that we are in an inertial reference frame that is stationary with respect to the center of mass of this two body system. Use the principle of conservation of mechanical energy (Kf+ Uf=Ki +Ui ) to find the following when the center-to-center separation is 0.5Ri:

(a) the total kinetic energy of the system,

(b) the kinetic energy of each body,

(c) the speed of each body relative to us, and

(d) the speed of body Brelative to body A. Next assume that we are in a reference frame attached to body A(we ride on the body). Now we see body Bfall from rest toward us. From this reference frame, again useKf+Uf=Ki+Uito find the following when the center-to-center separation is0.5Ri:

(e) the kinetic energy of body Band

(f) the speed of body Brelative to body A.

(g) Why are the answers to (d) and (f) different? Which answer is correct?

Question: In a shuttle craft of mass m = 3.00 kg , Captain Janeway orbits a planet of mass M=9.50ร—1025kg , in a circular orbit of radiusr=4.20ร—107m .What are (a) the period of the orbit and (b) the speed of the shuttle craft? Janeway briefly fires a forward pointing thruster, reducing her speeds by 2.00%. Just then, what are (c) the speed, (d) the kinetic energy, (e) the gravitational potential energy, and (f) the mechanical energy of the shuttle craft? (g) What is the semi major axis of the elliptical orbit now taken by the craft? (h)What is the difference between the period of the original circular orbit and that of the new elliptical orbit? (i) Which orbit has the smaller period?

In Figure (a), particleAis fixed in place atx=-0.20m on thexaxis and particleB, with a mass of 1.0 kg, is fixed in place at the origin. ParticleC(not shown) can be moved along thexaxis, between particleBandx=โˆž.Figure (b)shows thexcomponentFnet,xof the net gravitational force on particleBdue to particlesAandC, as a function of positionxof particleC. The plot actually extends to the right, approaching an asymptote ofโˆ’4.17ร—1010Nasโ†’โˆž. What are the masses of (a) particleAand (b) particleC?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free