Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In a real refrigerator, the low-temperature coils are at-13°C , and the compressed gas in the condenser is at26°C . What is the theoretical coefficient of performance?

Short Answer

Expert verified

The theoretical coefficient of performance is 6.67

Step by step solution

01

The given data

The low-temperature coil in the condenser,

The compressed gas temperature in the condenser,

02

Understanding the concept of the Carnot refrigerator

In an ideal refrigerator, all processes are reversible and no wasteful energy transfer occurs. The theoretical coefficient of performance is the ratio of heat from the low-temperature reservoir to the least amount of work. By using this ratio, we can calculate the coefficient of performance.

Formula:

The coefficient of the Carnot refrigerator, K=TLTH-TL (1)

03

Calculation of the theoretical coefficient of performance

By substituting temperature values in equation (1), we can get the coefficient of performance of the refrigerator as given:

K=260K299K-260K=260K39K=6.67

Hence, the value of the coefficient of performance is 6.67.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A Carnot refrigerator extracts 35.0 kJ as heat during each cycle, operating with a coefficient of performance of 4.60 . What are (a) the energy per cycle transferred as heat to the room and (b) the work done per cycle?

Energy can be removed from water as heat at and even below the normal freezing point (0.0°Cat atmospheric pressure) without causing the water to freeze; the water is then said to be supercooled. Suppose a 1.00 gwater drop is super-cooled until its temperature is that of the surrounding air, which is at-5.00°C. The drop then suddenly and irreversibly freezes, transferring energy to the air as heat. What is the entropy change for the drop? (Hint: Use a three-step reversible process as if the water were taken through the normal freezing point.) The specific heat of ice is2220J/kg.K.

An inventor has built an engine X and claims that its efficiency X is greater than the efficiency of an ideal engine operating between the same two temperatures. Suppose you couple engine X to an ideal refrigerator (Fig. 20-34a) and adjust the cycle of engine X so that the work per cycle it provides equals the work per cycle required by the ideal refrigerator. Treat this combination as a single unit and show that if the inventor’s claim were true(ifεx>ε), the combined unit would act as a perfect refrigerator (Fig. 20-34b), transferring energy as heat from the low-temperature reservoir to the high-temperature reservoir without the need for work.

A box contains Nmolecules. Consider two configurations: Configuration Awith an equal division of the molecules between the two halves of the box, and configuration Bwith 60.0%of the molecules in the left half of the box and 40.0%in the right half. For N =50, what are (a) the multiplicity WAof configuration A, (b) the multiplicityWb of configuration B, and (c) the ratiofB/Aof the time the system spends in configuration Bto the time it spends in configuration A? For N =100, what are (d)WA, (e)WB, and (f)fA/B? ForN =200, what are (g)WA, (h)WB, and (i)fA/B? ( j) With increasingN, doesincrease, decrease, or remain the same?

As a sample of nitrogen gas (N2) undergoes a temperature increase at constant volume, the distribution of molecular speeds increases. That is, the probability distribution function P(v)for the molecules spreads to higher speed values, as suggested in Fig. 19-8b. One way to report the spread in P(v)is to measure the differencev between the most probable speedvpand the rms speedvrms. When P(v) spreads to higher speeds,v increases. Assume that the gas is ideal and the N2 molecules rotate but do not oscillate. For 1.5 mol, an initial temperature of 250 K, and a final temperature of 500 K, what are (a) the initial differencevi, (b) the final difference,vf, and (c) the entropy changeS for the gas?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free