Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Curve a in Fig. 31-21 gives the impedance Z of a driven RC circuit versus the driving angular frequency ωd. The other two curves are similar but for different values of resistance R and capacitance C. Rank the three curves according to the corresponding value of R, greatest first.

Short Answer

Expert verified

According to the value of resistance, the circuits are ranked as Circuitc>Circuitb>Circuita.

Step by step solution

01

The given data

  1. The three circuits have different resistors and capacitors.
  2. Curve b and curve c are similar.
02

Understanding the concept of impedance of a circuit

The impedance of the RC circuit is the effective resistance of an electric circuit or component to alternating current, arising from the combined effects of resistance and reactance. Thus, it depends on the resistance and the reactance of the capacitor. The reactance of the capacitor varies with the angular frequency of the oscillation.

Formula:

The impedance of a RC circuit,Z=R2+1(ωC)2 (i)

03

Calculation of the ranking of the circuits according to their resistances

The analysis of the formula of equation (i) gives us the information that as ωincreases, the value of decreases 1ωC2. Thus, for higher values of ω, the capacitive reactance becomes less significant as compared to the resistance.

Thus, the graph of the impedance gives information about the resistance R at higher frequencies.

From the graph, we can see that at higher frequencies, the graph of circuit c has the highest resistance than circuit a and circuit b.

Hence, we rank the circuits in decreasing order of R as Circuitc>Circuitb>Circuita.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In an oscillating LCcircuit withC=64.0μF, the current is given byi=(1.60)sin(2500t+0.680), where tis in seconds, Iin amperes, and the phase constant in radians.(a) How soon aftert=0will the current reach its maximum value? (b) What is the inductance L? (c) What is the total energy?

A transformer has 500primary turns and 1012 secondary turns. (a) If role="math" localid="1663224210090" Vpis 120 V(RMS),whatVs is with an open circuit? (b) If the secondary now has a resistive load ofrole="math" localid="1663224020026" 15Ω, what is the current in the primary? (c) If the secondary now has a resistive load of 15Ωwhat is the current in the secondary?

Figure 31-36 shows an ac generator connected to a “black box” through a pair of terminals. The box contains an RLC circuit, possibly even a multiloop circuit, whose elements and connections we do not know. Measurements outside the box reveal thatε(t)=(75.0V)sin(ωdt)and i(t)=(1.20A)sin(ωdt+42.0°).

An ac generator with emfε=εmsinωdt, whereεm=25.0Vandωd=377rad/s, is connected to a4.15μFcapacitor. (a) What is the maximum value of the current? (b) When the current is a maximum, what is the emf of the generator? (c) When the emf of the generator isεm=-12.5Vand increasing in magnitude, what is the current?

The energy in an oscillating LCcircuit containing an1.25Hinductor is5.70μJ. The maximum charge on the capacitor is175μC. For a mechanical system with the same period, (a)Find the mass. (b) Find the spring constant. (c) Find the maximum displacement. (d) Find the maximum speed.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free