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Figure 26-19 shows four situations in which positive and negative charges move horizontally and gives the rate at which each charge moves. Rank the situations according to the effective current through the regions, greatest first.

Short Answer

Expert verified

The ranking of situations according to the effective current through the given regions isla=lb=lc>ld

Step by step solution

01

The given data

Figure 26-19 is the region of the current’s flow.

02

Understanding the concept of the current

Electrical charge carriers, such as electrons, flow as current. From negative to positive points, current flows.Taking the direction of positive charge as positive, we can find the net current in the region by adding the rate at which the charges move.

Formula:

The net current according to the current equation, l=l1+l2 …(i)

03

Calculation of the rank of situations according to effective current

The direction of the positive charge is the direction of the current. Hence,

For region a), the net current is given by:la=7C/s

For region b), the net current is given using equation (i) as:

la=4+3=7C/s

For region c), the net current is given using equation (i) as:

lc=5+2=7C/s

For region d), the net current is given using equation (i) as:

ld=6-1=5C/s

So the ranking of the effective current isla=lb=lc>ld

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Most popular questions from this chapter

A steady beam of alpha particles (q2e) traveling with constant kinetic energy 20 MeV carries a current of0.25 A . (a) If the beam is directed perpendicular to a flat surface, how many alpha particles strike the surface in 3.0 s? (b) At any instant, how many alpha particles are there in a given 20 cmlength of the beam? (c) Through what potential difference is it necessary to accelerate each alpha particle from rest to bring it to energy of 20 MeV ?

What is the current in a wire of radius R=3.40 mm if the magnitude of the current density is given by (a)Ja=J0r/Rand(b)Jb=J0(1-r/R), in which ris the radial distance and J0=5.50×104A/m2? (c) Which function maximizes the current density near the wire’s surface?

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(b) does this same “doubling temperature” hold for all copper conductors, regardless of shape or size?

A wire 4.00mlong and 6.00mmin diameter has a resistance of15.0. A potential difference of 23.0 Vis applied between the ends. (a) What is the current in the wire? (b) What is the magnitude of the current density? (c) Calculate the resistivity of the wire material. (d) Using Table, identify the material.

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