Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A 120 Vpotential difference is applied to a space heater whose resistance is 14Ωwhen hot. (a) At what rate is electrical energy transferred to thermal energy? (b) What is the cost for 5.0h at US $0.05/kW.h?

Short Answer

Expert verified
  1. The rate of transfer of the electrical energy to thermal energy is 1.0 kW.
  2. The cost of this energy transfer for 5h at US $0.05/kw.h is US $0.25.

Step by step solution

01

The given data

  1. Potential difference, V = 120 V
  2. Resistance of the heater,R=14Ω
  3. Time of transfer, t = 0.05h
  4. Cost per energy isUS $0.05/kw.h
02

Understanding the concept of rate of energy transfer

Using the concept of power, we can get the required rate of electrical energy transfer to thermal energy. Then, using this value, we can get the cost per transfer of the energy.

Formula:

The rate of energy transfer from one form to another, P=V2/R …(i)

03

(a) Calculation of the rate of the energy transfer

Using the given data in equation (i), we can get the rate of transferred electrical energy to thermal energy as follows:

P=120V214Ω=1.0×103W=1.0kW

Hence, the value of the rate of energy is 1.0kW.

04

(b) Calculation of the cost value

The cost of the energy transfer using the given data can be given as follows:

Cost=1kW5h0.05$/kW.h=US$0.25

Hence, the value of the required cost is US$0.25.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The magnitude J(r) of the current density in a certain cylindrical wire is given as a function of radial distance from the centre of the wire’s cross section as J(r) = Br, where ris in meters, Jis in amperes per square meter, andB=2.00×105A/m3.This function applies out to the wire’s radius of 2.00 mm. How much current is contained within the width of a thin ring concentric with the wire if the ring has a radial width of10.0μmand is at a radial distance of 1.20 mm?

A current is established in a gas discharge tube when a sufficiently high potential difference is applied across the two electrodes in the tube. The gas ionizes; electrons move toward the positive terminal and singly charged positive ions toward the negative terminal.(a)What is the current in a hydrogen discharge tube in which 3.1×1018electrons andlocalid="1661417709864" 1.1×1018protons move past a cross-sectional area of the tube each second? (b) Is the direction of the current densityJtoward or away from the negative terminal?

A small but measurable current of1.2×10-10Aexists in a copper wire whose diameter is 2.5 mm.The number of charge carriers per unit volume is8.49×1028m-3. Assuming the current is uniform, calculate the (a) current density and (b) electron drift speed.

A cylindrical metal rod is 1.60 mlong and 5.50 min diameter. The resistance between its two ends (at 20°) is 1.09×10-3Ω. (a) What is the material? (b) A round disk,2.00 cm in diameter and 1.00 mmthick, is formed of the same material. What is the resistance between the round faces, assuming that each face is an equi-potential surface?

A cylindrical resistor of radius 5.00mm and length2.0 cmis made of material that has a resistivity of 3.5×10-5Ω.m .What are (a) the magnitude of the current density and (b) the potential difference when the energy dissipation rate in the resistor is 1.0 W?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free