Question

How many megacoulombs of positive charge are in $\mathbf{1}\mathbf{.00}\mathbf{}\mathbf{mol}$of neutral molecular-hydrogen gas (${\mathbf{H}}_{\mathbf{2}}$)?

Short answer

The value of the positive charge in the hydrogen molecule is$0.19\text{MC}$.

Step-by-step solution

The given data

1. Neutral molecular-hydrogen gas (${\mathrm{H}}_2$) of $1.00\text{mol}$is given.
2. Avogadro number in one mole of a substance,${\mathrm{N}}_{\mathrm{A}}=6.023\times {10}^{23}\text{\hspace{0.17em}molecules}$

Understanding the concept of Coulomb’s law

Using the concept of quantization of charges, we can get the net charge in the given mol of hydrogen gas.

Formula:

The total charge of a molecule respective to the Avogadro number,

$\mathrm{Q}={\mathrm{N}}_{\mathrm{A}}\mathrm{q},\text{where,}\mathrm{q}=\text{no.ofelectrons}\times \text{electroniccharge}$ (i)

Calculation of the total positive charge in mega coulombs 

There are two protons (each with charge q = +e) in each molecule.

So, using the formula of equation (i), we can get the positive charge value in mega coulombs as given:

$\begin{array}{c}\mathrm{Q}=(6.023\times {10}^{23})\left(2\right)(1.60\times {10}^{-19}\text{C})\\ =1.90\times {10}^5\text{C}\\ =0.19\text{MC}\end{array}$

Hence, the value of the positive charge is$0.19\text{MC}$