Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

An isolated atom of germanium has 32 electrons, arranged in subshells according to this scheme:1s22s22p63s23p63d104s24p2 This element has the same crystal structure as silicon and, like silicon, is a semiconductor. Which of these electrons form the valence band of crystalline germanium?

Short Answer

Expert verified

The electrons from subshells 4s and 4p will form the valence band isolated atom of germanium.

Step by step solution

01

The given data

An isolated atom of germanium has 32 electrons arranged in subshells: 1s22s22p63s23p63d104s24p2

02

Semiconductors

Materials whole resistivity values lie between that of conductors and insulators are called semiconductors. Examples are silicon, germanium, etc. At room temperatures the number of free charge carriers is very less and hence they act like insulators. As we increase the temperature, the number of charge carriers that are free to move increase rapidly and hence they start behaving as conductors.

03

Calculation of the electrons that form the valence band

From the concept, we can get that the outermost subshells of an atom that are far from the nucleus of the atom form the valence band of an atomic structure.

Hence, according to the atomic orbital concept, there are 4 electrons in the valence band due to the contribution from subshells and that is the highest filled band.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

At 1000K, the fraction of the conduction electrons in a metal that have energies greater than the Fermi energy is equal to the area under the curve of Fig. 41-8bbeyond EF divided by the area under the entire curve. It is difficult to find these areas by direct integration. However, an approximation to this fraction at any temperature T is frac=3kT2EF.

Note that frac = 0 for T = 0 K, just as we would expect. What is this fraction for copper at (a) 300 K and (b) 1000 K? For copper EF=7.0eV. (c) Check your answers by numerical integration using Eq. 41-7.

The compound gallium arsenide is a commonly used semiconductor, has an energy gap Egof1.43eV. Its crystal structure is like that of silicon, except that half the silicon atoms are replaced by gallium atoms and half by arsenic atoms. Draw a flattened-out sketch of the gallium arsenide lattice, following the pattern of Fig. 41-10a.What is the net charge of the (a) gallium and (b) arsenic ion core? (c) How many electrons per bond are there? (Hint:Consult the periodic table in Appendix G.)

Silver is a monovalent metal. Calculate (a) the number density of conduction electrons, (b) the Fermi energy, (c) the Fermi speed and (d) the de Broglie wavelength corresponding to this electron speed. See Appendix F for the needed data on silver.

At what pressure, in atmospheres, would the number of molecules per unit volume in an ideal gas be equal to the number density of the conduction electrons in copper, with both gas and copper at temperature T =300K?

A silicon sample is doped with atoms having donor states 0.110eV below the bottom of the conduction band. (The energy gap in silicon is 1.11eV ) If each of these donor states is occupied with a probability of 5.00ร—10-5at T=300K, (a) is the Fermi level above or below the top of the silicon valence band and (b) how far above or below? (c) What then is the probability that a state at the bottom of the silicon conduction band is occupied?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free