Chapter 41: Q6P (page 1273)
Use Eq. 41-9 to verify 7.0eV as copper’s Fermi energy.
Short Answer
The Fermi energy of the copper metal is 7.0eV .
Chapter 41: Q6P (page 1273)
Use Eq. 41-9 to verify 7.0eV as copper’s Fermi energy.
The Fermi energy of the copper metal is 7.0eV .
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Verify the numerical factor 0.121 in Eq. 41-9.
In a particular crystal, the highest occupied band is full. The crystal is transparent to light of wavelengths longer than 295nm but opaque at shorter wavelengths. Calculate, in electron-volts, the gap between the highest occupied band and the next higher (empty) band for this material.
The occupancy probability function (Eq. 41-6) can be applied to semiconductors as well as to metals. In semiconductors the Fermi energy is close to the midpoint of the gap between the valence band and the conduction band. For germanium, the gap width is 0.67eV. What is the probability that (a) a state at the bottom of the conduction band is occupied and (b) a state at the top of the valence band is not occupied? Assume that T = 290K. (Note:In a pure semiconductor, the Fermi energy lies symmetrically between the population of conduction electrons and the population of holes and thus is at the center of the gap. There need not be an available state at the location of the Fermi energy.)
At what pressure, in atmospheres, would the number of molecules per unit volume in an ideal gas be equal to the number density of the conduction electrons in copper, with both gas and copper at temperature T =300K?
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