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The Fermi energy of copper is 7.0eV. Verify that the corresponding Fermi speed is 1600 km/s.

Short Answer

Expert verified

The corresponding Fermi speed for Fermi energy value 7.0 eV is 1600 km/s .

Step by step solution

01

The given data

Fermi energy of copper, EF=7.0eV

02

Understanding the concept of energy and speed

The energy of a body due to its speed, is known as kinetic energy of the body. The total work done in moving from one place to another is stored in the bodyin the form of kinetic energy.

Formula:

The kinetic energy of a system,E=12mv2 (i)

03

Calculation of the Fermi energy

Using the given data of Fermi energy of copper in equation (i), we can get the value of the corresponding Fermi speed as follows:

vf=2EFm=c2EFmc2=3×105km/s27.0eV5.11×105eV=1.6×103km/s

Hence, the value of the speed is 1.6×103km/s.

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Most popular questions from this chapter

In Eq. 41-6 let, E-EF=E=1.00eV. (a) At what temperature does the result of using this equation differ by 1% from the result of using the classical Boltzmann equation P(E)=e-E/kT(which is Eq. 41-1 with two changes in notation)? (b) At what temperature do the results from these two equations differ by 10%?

For an ideal p-njunction rectifier with a sharp boundary between its two semiconducting sides, the current Iis related to the potential difference Vacross the rectifier by l=l0(eeV/kT-1), where l0, which depends on the materials but not on Ior V, is called the reverse saturation current.The potential difference Vis positive if the rectifier is forward-biased and negative if it is back-biased. (a) Verify that this expression predicts the behavior of a junction rectifier by graphing Iversus Vfrom to -12Vto+0.12V. Take T=300Kand l0=5.0nA. (b) For the same temperature, calculate the ratio of the current for a 0.50 V forward bias to the current for a 0.50 V back bias.

At T = 300K, how far above the Fermi energy is a state for which the probability of occupation by a conduction electron is 0.10?

What is the probability that a state 0.0620eV above the Fermi energy will be occupied at (a) T = OK and (b) T = 320K?

(a) Using the result of Problem 23 and 7.00eVfor copper’s Fermi energy, determine how much energy would be released by the conduction electrons in a copper coin with mass3.10g if we could suddenly turn off the Pauli exclusion principle. (b) For how long would this amount of energy light a100 Wlamp? (Note: There is no way to turn off the Pauli principle!)

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