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Figure 41-1ashows 14 atoms that represent the unit cell of copper. However, because each of these atoms is shared with one or more adjoining unit cells, only a fraction of each atom belongs to the unit cell shown. What is the number of atoms per unit cell for copper? (To answer, count up the fractional atoms belonging to a single unit cell.)

Short Answer

Expert verified

The number of atoms per unit cell is 4.

Step by step solution

01

The given data

The unit cell of the copper shows the representation of 14 atoms.

02

Understanding the concept of lattice structure of copper

A lattice structure is a three-dimension open structure that is made up of more than one repeating unit cell of an atom. The cells define the connectivity of the constituent atoms in the unit cell structure. They can be of mainly four types of lattice structures: FCC, BCC, HCP, and simple cubic. Now, here the given unit cell of copper has an FCC structure. The total number of atoms per unit cell is calculated by calculating the atoms’ contributions that are placed at the corners and face constituting the structure.

03

Calculation of the number of atoms per unit cell

As the lattice structure copper consisting of 14 electrons is an FCC structure, thus the contribution to the structure is only from the face and corner atoms.

The contribution of each corner atom per unit cell of copper is 18. So, the total contribution by 8 corner atoms is 1.

The contribution of each face atom per unit cell of copper is 12. Thus, the contribution of 6 face atoms per unit cell of copper is 3.

Now, the total contribution of the FCC lattice in the copper unit cell is given by:

18×8+12×6=4

Hence, the number of atoms per unit cell of copper is 4.

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Most popular questions from this chapter

For an ideal p-njunction rectifier with a sharp boundary between its two semiconducting sides, the current Iis related to the potential difference Vacross the rectifier by l=l0(eeV/kT-1), where l0, which depends on the materials but not on Ior V, is called the reverse saturation current.The potential difference Vis positive if the rectifier is forward-biased and negative if it is back-biased. (a) Verify that this expression predicts the behavior of a junction rectifier by graphing Iversus Vfrom to -12Vto+0.12V. Take T=300Kand l0=5.0nA. (b) For the same temperature, calculate the ratio of the current for a 0.50 V forward bias to the current for a 0.50 V back bias.

Assume that the total volume of a metal sample is the sum of the volume occupied by the metal ions making up the lattice and the (separate) volume occupied by the conduction electrons. The density and molar mass of sodium (a metal) are 971kg/m3and 23.g/mol, respectively; assume the radius of the Na+ ion is . (a) What percent of the volume of a sample of metallic sodium is occupied by its conduction electrons? (b) Carry out the same calculation for copper, which has density, molar mass, and ionic radius of 8960kg/m3, 63.5g/mol, and 135 pm, respectively. (c) For which of these metals do you think the conduction electrons behave more like a free-electron gas?

Silver melts at 961°C. At the melting point, what fraction of the conduction electrons is in states with energies greater than the Fermi energy of 5.5 eV? (See Problem 21)

What is the probability that a state 0.0620eV above the Fermi energy will be occupied at (a) T = OK and (b) T = 320K?

At 1000K, the fraction of the conduction electrons in a metal that have energies greater than the Fermi energy is equal to the area under the curve of Fig. 41-8bbeyond EF divided by the area under the entire curve. It is difficult to find these areas by direct integration. However, an approximation to this fraction at any temperature T is frac=3kT2EF.

Note that frac = 0 for T = 0 K, just as we would expect. What is this fraction for copper at (a) 300 K and (b) 1000 K? For copper EF=7.0eV. (c) Check your answers by numerical integration using Eq. 41-7.

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