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A capacitor with initial charge qois discharged through a resistor. What multiple of the time constant ζ gives the time the capacitor takes to lose (a) the first one-third of its charge and (b) two-thirds of its charge?

Short Answer

Expert verified
  1. The multiple of the time constant that the capacitor takes to lose the first one-third of its charge is 0.41.
  2. The multiple of the time constant that the capacitor takes to lose the first two-thirds of its charge is 1.1.

Step by step solution

01

The given data

A capacitor with initial charge qo is discharged through a resistor.

02

Understanding the concept of time constant

Using the charging and discharging concept of the capacitor, we can get the required charge relation using the time constant of the RC circuit. Thus, the condition will give the multiplication value of the time constant.

Formula:

The charge equation of an RC circuit, q=qoe-t/RC (1)

03

a) Calculation of the multiple of the time constant to lose the first one-third of its charge

For the given condition of the charge stored in the capacitor q=2qo/3, the multiple of the time constant ζthat the capacitor takes to lose the first one-third of its charge can be given using equation (1) as follows:

t=ζlnqoq=ζlnqo2qo/3=ζln32=0.41ζ

Hence, the multiple values of the time constant are 0.41.

04

b) Calculation of the multiple of the time constant to lose the first two-thirds of its charge

For the given condition of the charge stored in the capacitor q=qo/3, the multiple of the time constant ζthat the capacitor takes to lose the first two-thirds of its charge can be given using equation (1) as follows:

t=ζlnqoq=ζlnqoqo/3=ζln3=1.1ζ

Hence, the multiple values of the time constant are 1.1.

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