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Two particles Pand Qare released from rest 1.0 m apart. Phas a mass 0.10kg of aand Qa mass of 0.030 kg.Pand Qattract each other with a constant force of1.0×1.0-2N. No external forces act on the system.(a) What is the speed of the center of mass of Pand Qwhen the separation is 0.50 m?(b) At what distance from P’s original position do the particles collide?

Short Answer

Expert verified
  1. Speed of the center of mass of P and Q when separation is 0.5 m is0ms
  2. Distance from P's original position do the particles collide is 0.75 m.

Step by step solution

01

Step 1: Given

  1. Mass of P is,M1=0.1kg .
  2. Mass of Q is,M2=0.3kg .
  3. Separation distance between P and Q is 1 m .
02

Determining the concept

Usetheformula for center of mass to findtheposition.Centre of mass is the point, which represent the mean position of a matter of a body.

Formula is as follow:

Xcm=M1x1+M2x2M1+M2

Here, M1, M2 are masses, x1, x2 are distances of points from centre and Xcm is centre of mass.

03

(a) Determining the speed of the center of mass of P and Q when separation is

As there is no external force acting initially on the stationary particles P and Q, their center of mass does not move.

Hence, speed of the center of mass of P and Q when separation is 0.5 m is0ms

04

(b) Determining the distance from P's  original position do the particles collide

Let’s assume that initially particle A is at x = 0 and particle Q is at x = 1.The particles will collide at their center of mass. Then, according to the concept of center of mass,

Xcom=M1x1+M2x2M1+M2Xcom=0.1(0)+(0.3)(1)(0.1+0.3)Xcom=0.75m

Hence, distance from P's original position do the particles collide is 0.75 m.

Therefore, the speed of the center of mass from the external force acting on stationary objects can be found. Using the concept of center of mass, the distance at which objects collide can be found.

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