Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

An electron in an atom of gold is in a state with n = 4. Which of these values of are possible for it:-3, 0, 2, 3, 4, 5?

Short Answer

Expert verified

The possible values of l with are 0, 2 and 3.

Step by step solution

01

The given data

The given quantum state of the electron, n = 4

02

Understanding the concept of the electronic configuration

The number of possible l states of an atomic orbital for a given quantum number n range from 0 to n-1 positive integer values. Here, l represents the azimuthally quantum state of an electronic configuration.

03

Calculation of all possible values of l

Using the concept, we can say that the number of possible states of l for n = 4 is from 0 to (n - 1) integer values. They are 0, 1, 2, and 3.

Hence, the possible values according to the question are 0, 2, and 3.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The beam from an argon laser (of wavelength 515 nm) has a diameter 3.00 mm of and a continuous energy output rate of 5.00 W. The beam is focused onto a diffuse surface by a lens whose focal length f is 3.50 cm . A diffraction pattern such as that of Fig. 36-10 is formed, the radius of the central disk being given by R=1.22fฮปd(see Eq. 36-12 and Fig. 36-14). The central disk can be shown to contain 84% of the incident power. (a) What is the radius of the central disk? (b) What is the average intensity (power per unit area) in the incident beam? (c) What is the average intensity in the central disk?

A tungsten (Z=74) target is bombarded by electrons in an x-ray tube. The K,L and M energy levels for tungsten (compare Fig. 40-15) have the energies 69.5 keV,11.3 keV, and 2.30 keV respectively. (a) What is the minimum value of the accelerating potential that will permit the production of the characteristickฮฑ andkฮฒ lines of tungsten? (b) For this same accelerating potential, what is ฮปmin? What are the (c) kฮฑand (d)kฮฒ wavelengths?

Through what minimum potential difference must an electron in an x-ray tube be accelerated so that it can produce x-rays with a wavelength of 0.100 nm ?

A hydrogen atom in its ground state actually has two possible, closely spaced energy levels because the electron is in the magnetic field Bโ†’of the proton (the nucleus). Accordingly, energy is associated with the orientation of the electronโ€™s magnetic moment ฮผโ†’relative to Bโ†’, and the electron is said to be either spin up (higher energy) or spin down (lower energy) in that field. If the electron is excited to the higher energy level, it can de-excite by spin-flipping and emitting a photon. The wavelength associated with that photon is 21 cm. (Such a process occurs extensively in the Milky Way galaxy, and reception of the 21 cm radiation by radio telescopes reveals where hydrogen gas lies between stars.) What is the effective magnitude of Bโ†’as experienced by the electron in the ground-state hydrogen atom?

When electrons bombard a molybdenum target, they produce both continuous and characteristic x-rays as shown in Fig. 40-13. In that figure the kinetic energy of the incident electrons is 35.0 keV. If the accelerating potential is increased to 50.0 keV, (a) what is the value of ฮปmin, and (b) do the wavelengths of the role="math" localid="1661497027757" kฮฑand kฮฒlines increase, decrease, or remain the same?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free