Chapter 8: Problem 39
Consider a regenerative vapor power cycle with two feedwater heaters, a closed one and an open one. Steam enters the first turbine stage at \(8 \mathrm{MPa}, 480^{\circ} \mathrm{C}\), and expands to \(2 \mathrm{MPa}\). Some steam is extracted at \(2 \mathrm{MPa}\) and fed to the closed feedwater heater. The remainder expands through the second-stage turbine to \(0.3 \mathrm{MPa}\), where an additional amount is extracted and fed into the open feedwater heater, which operates at \(0.3 \mathrm{MPa}\). The steam expanding through the third-stage turbine exits at the condenser pressure of \(8 \mathrm{kPa}\). Feedwater leaves the closed heater at \(205^{\circ} \mathrm{C}, 8 \mathrm{MPa}\), and condensate exiting as saturated liquid at \(2 \mathrm{MPa}\) is trapped into the open heater. Saturated liquid at \(0.3 \mathrm{MPa}\) leaves the open feedwater heater. The net power output of the cycle is \(100 \mathrm{MW}\). If the turbine stages and pumps are isentropic, determine (a) the thermal efficiency. (b) the mass flow rate of steam entering the first turbine, in \(\mathrm{kg} / \mathrm{h}\).
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