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Superheated steam at \(18 \mathrm{MPa}, 560^{\circ} \mathrm{C}\), enters the turbine of a vapor power plant. The pressure at the exit of the turbine is \(0.06\) bar, and liquid leaves the condenser at \(0.045\) bar, \(26^{\circ} \mathrm{C}\). The pressure is increased to \(18.2 \mathrm{MPa}\) across the pump. The turbine and pump have isentropic efficiencies of 82 and \(77 \%\), respectively. For the cycle, determine (a) the net work per unit mass of steam flow, in \(\mathrm{kJ} / \mathrm{kg}\). (b) the heat transfer to steam passing through the boiler, in kJ per \(\mathrm{kg}\) of steam flowing. (c) the thermal efficiency. (d) the heat transfer to cooling water passing through the condenser, in \(\mathrm{kJ}\) per \(\mathrm{kg}\) of steam condensed.

Short Answer

Expert verified
The steps involve determining enthalpies at various points, adjusting for efficiencies, and calculating net work, heat transfer, and efficiency.

Step by step solution

01

- Analyze Turbine Work per Unit Mass

Determine the state properties at the entrance and exit of the turbine. Use steam tables to find the enthalpies and entropies of the superheated steam at 18 MPa and 560°C. The properties at the exit (0.06 bar) can be determined assuming isentropic expansion.
02

- Calculate Turbine Work with Isentropic Efficiency

Use the efficiency definition to adjust the turbine work output. First, calculate the work assuming isentropic conditions and then apply the efficiency: \[ W_{turbine} = \text{Eff_{turbine}} \times (h_1 - h_{2s}) \]
03

- Determine Pump Work per Unit Mass

Analyze the pump state's properties at the entrance (0.045 bar, 26°C) and determine pump work for increasing the pressure to 18.2 MPa. Apply isentropic efficiency to get actual pump work: \[ W_{pump} = \frac{W_{pump,isen}}{\text{Eff_{pump}}} \]
04

- Calculate Net Work per Unit Mass

Subtract the pump work from the turbine work: \[ W_{net} = W_{turbine} - W_{pump} \]
05

- Evaluate Heat Transfer in the Boiler per Unit Mass

Find the enthalpy before and after the boiler by evaluating the steam conditions using steam tables. The heat added in the boiler corresponds to the enthalpy difference: \[ q_{in} = h_1 - h_{cond} \]
06

- Determine Thermal Efficiency

The thermal efficiency is calculated by dividing the net work by the heat added: \[ \text{Efficiency} = \frac{W_{net}}{q_{in}} \]
07

- Evaluate Heat Transfer in the Condenser per Unit Mass

The heat rejected in the condenser can be calculated by finding the enthalpy difference as the steam exits the condenser (0.045 bar, liquid). \[ q_{out} = h_{2} - h_{cond} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Isentropic Efficiency
In a vapor power plant, understanding isentropic efficiency is crucial for analyzing the performance of turbines and pumps. Isentropic efficiency measures how closely a real process (like in a turbine or a pump) approaches an ideal isentropic process (a process with no entropy change). For the turbine, isentropic efficiency \(\text{Eff}_{\text{turbine}}\) can be calculated as follows: \[ \text{Eff}_{\text{turbine}} = \frac{h_1 - h_{2\text{s}}}{h_1 - h_2} \] Here, \(h_1\) is the enthalpy at the turbine inlet, \(h_{2\text{s}}\) is the enthalpy at the turbine outlet in the isentropic case, and \(h_2\) is the actual enthalpy at the turbine outlet. Similarly, for a pump, the isentropic efficiency \(\text{Eff}_{\text{pump}}\) is given by: \[ \text{Eff}_{\text{pump}} = \frac{W_{\text{pump,isen}}}{W_{\text{pump}}} \] Here, \(W_{\text{pump,isen}}\) is the work input under isentropic conditions, and \(W_{\text{pump}}\) is the actual work input. These efficiencies are always less than 100%, indicating losses due to factors like friction and heat transfer.
Turbine Work Calculation
Calculating the work done by a turbine starts with using steam tables to determine the enthalpy values at the inlet and outlet. For the given example, we need the enthalpy \(h_1\) at 18 MPa and 560°C. Assuming isentropic expansion, we find \(h_{2\text{s}}\) at 0.06 bar. The actual turbine work comes from adjusting for isentropic efficiency: \[ W_{\text{turbine}} = \text{Eff}_{\text{turbine}} \times (h_1 - h_{2\text{s}}) \] By substituting the efficiency of 82% \( (\text{Eff}_{\text{turbine}} = 0.82)\), we get: \[ W_{\text{turbine}} = 0.82 \times (h_1 - h_{2\text{s}}) \] This formula accounts for the losses and gives the usable turbine work.
Pump Work Calculation
Pumps in vapor power plants increase the pressure of the fluid, requiring work input. To find the work needed, start by determining the enthalpy at the initial state (0.045 bar, 26°C) using steam tables. Calculate the ideal isentropic pump work (\text{\(W_{\text{pump,isen}})\) for raising the pressure to 18.2 MPa. This work is adjusted with the isentropic efficiency to find the actual work required: \[ W_{\text{pump}} = \frac{W_{\text{pump,isen}}}{\text{Eff}_{\text{pump}}} \] Given an efficiency \( \text{Eff}_{\text{pump}} \) of 77% (\text{0.77}), we have: \[ W_{\text{pump}} = \frac{W_{\text{pump,isen}}}{0.77} \] This calculation helps in understanding the energy required to operate the pump, accounting for real-world inefficiencies.
Thermal Efficiency
Thermal efficiency measures how well the power plant converts heat into work. It's defined as the ratio of net work output to the heat input: \[ \text{Thermal Efficiency} = \frac{W_{\text{net}}}{q_{\text{in}}} \] We already calculated the net work per unit mass \(W_{\text{net}}\): \[ W_{\text{net}} = W_{\text{turbine}} - W_{\text{pump}} \] For heat added in the boiler \( (q_{\text{in}})\), we use the enthalpy difference before and after the boiler: \[ q_{\text{in}} = h_1 - h_{\text{cond}} \] Thermal efficiency aids in evaluating power plant performance, showing how effectively the plant converts fuel energy into useful work.
Heat Transfer in Boiler
The boiler in a vapor power plant adds energy to the steam, necessary for powering the turbine. To find the heat transfer per unit mass: \[ q_{\text{in}} = h_1 - h_{\text{cond}} \] Here, \( h_1 \) is the enthalpy at the boiler exit, and \( h_{\text{cond}} \) is the enthalpy of liquid leaving the condenser. The steam tables are essential because they provide these enthalpy values. By subtracting the initial enthalpy from the final enthalpy, we obtain the heat added in the boiler. This calculation evaluates the energy input required to produce steam.
Steam Tables
Steam tables are indispensable tools for analyzing vapor power plants. They provide thermodynamic properties of water and steam at various temperatures and pressures. Key properties include enthalpy, entropy, and specific volume. For instance, to solve the problem:
  • Find enthalpy \( h_1 \) at 18 MPa and 560°C
  • Determine enthalpy \( h_{\text{cond}} \) at 0.045 bar, 26°C
  • Check enthalpy values for isentropic expansion \( h_{2s} \) at 0.06 bar
Using these tables helps us accurately perform calculations, ensuring we dimension the plant correctly and understand its performance. Hence, mastering how to read steam tables is fundamental for any engineering student.

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Most popular questions from this chapter

Steam at \(10 \mathrm{MPa}, 600^{\circ} \mathrm{C}\) enters the first-stage turbine of an ideal Rankine cycle with reheat. The steam leaving the reheat section of the steam generator is at \(500^{\circ} \mathrm{C}\), and the condenser pressure is \(6 \mathrm{kPa}\). If the quality at the exit of the secondstage turbine is \(90 \%\), determine the cycle thermal efficiency.

A power plant operates on a regenerative vapor power cycle with one open feedwater heater. Steam enters the first turbine stage at \(12 \mathrm{MPa}, 520^{\circ} \mathrm{C}\) and expands to \(1 \mathrm{MPa}\), where some of the steam is extracted and diverted to the open feedwater heater operating at \(1 \mathrm{MPa}\). The remaining steam expands through the second turbine stage to the condenser pressure of \(6 \mathrm{kPa}\). Saturated liquid exits the open feedwater heater at \(1 \mathrm{MPa}\). For isentropic processes in the turbines and pumps, determine for the cycle (a) the thermal efficiency and (b) the mass flow rate into the first turbine stage, in \(\mathrm{kg} / \mathrm{h}\), for a net power output of \(330 \mathrm{MW}\).

One way for power plants to meet peak demands is to use excess generation capacity during off-peak hours to produce ice, which can then be used as a low-temperature reservoir for condenser heat rejection during peak demand periods. Critically evaluate this concept for improved power plant utilization and write a report of your findings.

Refrigerant \(134 \mathrm{a}\) is the working fluid in a solar power plant operating on a Rankine cycle. Saturated vapor at \(60^{\circ} \mathrm{C}\) enters the turbine, and the condenser operates at a pressure of 6 bar. The rate of energy input to the collectors from solar radiation is \(0.4 \mathrm{~kW}\) per \(\mathrm{m}^{2}\) of collector surface area. Determine the \(\mathrm{min}\) imum possible solar collector surface area, in \(\mathrm{m}^{2}\), per \(\mathrm{kW}\) of power developed by the plant.

Steam enters the first turbine stage of a vapor power cycle with reheat and regeneration at \(32 \mathrm{MPa}, 600^{\circ} \mathrm{C}\), and expands to \(8 \mathrm{MPa}\). A portion of the flow is diverted to a closed feedwater heater at \(8 \mathrm{MPa}\), and the remainder is reheated to \(560^{\circ} \mathrm{C}\) before entering the second turbine stage. Expansion through the second turbine stage occurs to \(1 \mathrm{MPa}\), where another portion of the flow is diverted to a second closed feedwater heater at \(1 \mathrm{MPa}\). The remainder of the flow expands through the third turbine stage to \(0.15 \mathrm{MPa}\), where a portion of the flow is diverted to an open feedwater heater operating at \(0.15 \mathrm{MPa}\), and the rest expands through the fourth turbine stage to the condenser pressure of \(6 \mathrm{kPa}\). Condensate leaves each closed feedwater heater as saturated liquid at the respective extraction pressure. The feedwater streams leave each closed feedwater heater at a temperature equal to the saturation temperature at the respective extraction pressure. The condensate streams from the closed heaters each pass through traps into the next lower-pressure feedwater heater. Saturated liquid exiting the open heater is pumped to the steam generator pressure. If each turbine stage has an isentropic efficiency of \(85 \%\) and the pumps operate isentropically (a) sketch the layout of the cycle and number the principal state points. (b) determine the thermal efficiency of the cycle. (c) calculate the mass flow rate into the first turbine stage, in \(\mathrm{kg} / \mathrm{h}\), for a net power output of \(500 \mathrm{MW}\).

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