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An insulated, rigid tank is divided into two compartments by a frictionless, thermally conducting piston. One compartment initially contains 1 m3 of saturated water vapor at 4MPa and the other compartment contains 1 m3 of water vapor at 20MPa,800C. The piston is released and equilibrium is attained, with the piston experiencing no change of state. For the water as the system, determine (a) the final pressure, in MPa. (b) the final temperature, in C. (c) the amount of entropy produced, in kJ/K.

Short Answer

Expert verified
a) Final Pressure P_f=?? MPa. b) Final Temperature T_f= ?? °C c) Total Entropy Production deltaS = ?? kj/k.

Step by step solution

01

Define System and Initial Conditions

Consider two compartments with a frictionless, thermally conducting piston. The initial conditions are: Compartment 1 has 1 m³ of saturated water vapor at 4 MPa, and Compartment 2 has 1 m³ of water vapor at 20 MPa, 800°C.
02

Understand the Intermediate Process

When the piston is released, energy will be exchanged between the compartments until equilibrium is reached. Assume the final state has common pressure, temperature, and the piston does not change.
03

Utilize the Specific Volume Relationship

Use the fact that the total volume remains constant. The specific volumes of water vapor in both compartments must satisfy initial and final volume constraints. Let specific volumes be denoted as: Initial: 'u_1' for compartment 1 at 4 MPa saturation 'u_2' for compartment 2 at 20 MPa, 800°C Final: 'u_f' for the final equilibrium state
04

Determine the Final Equilibrium State Condition

From the volume relation, (V1+V2)/Total Mass = final specific volume u_f=(u_1+u_2)/2 . Identify the equilibrium temperature (T_f) and pressure (P_f) using standard steam tables.
05

Calculate Final Pressure and Temperature

Using the standard steam tables, extract specific volumes corresponding to the given pressure and temperature for both initial compartments. Calculate the final equilibrium specific volume and find matching P_f and T_f in steam tables.
06

Entropy Calculation

Use entropy formula for individual states and system entropy change: delta S = S2 - S1 . Generate entropy tables to find individual entropies using initial and final steam tables. Calculate the entropy production using these individual entropy values and the final equilibrium stage.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

saturated water vapor
Saturated water vapor is a condition where water exists entirely in the vapor phase at a specific temperature and pressure. At this state, the vapor is in equilibrium with liquid water, meaning no net evaporation or condensation occurs. In the given problem, one of the compartments initially contains 1 m³ of saturated water vapor at 4 MPa. It's important to note that the term 'saturated' indicates that any additional heat will start converting the liquid water into vapor without changing the temperature, assuming pressure remains constant. This is a vital concept in thermodynamics, as it sets a baseline for many calculations related to energy transfer and equilibrium states.
specific volume
Specific volume is a property of matter that describes the volume occupied by a unit mass of a substance. It is the inverse of density and is particularly useful in thermodynamics when dealing with gases and vapors. In the problem, the specific volume helps determine the equilibrium state of the system. The specific volume for each initial compartment is crucial: for the saturated water vapor at 4 MPa and for the superheated steam at 20 MPa, 800°C. The final specific volume, which remains constant in this closed and insulated system, allows us to find the equilibrium pressure and temperature. You can find specific volume values in steam tables, which are indispensable for solving such problems.
entropy production
Entropy production is a measure of the irreversibility of a process in a thermodynamic system. It represents the amount of entropy created within the system due to processes like heat transfer, fluid friction, or mixing of different substances. In the given problem, calculating the amount of entropy produced involves understanding the entropy change in both compartments as they reach equilibrium. The formula ΔS=S2S1 is used, where S1 and S2 represent the initial and final entropy states, respectively. By using steam tables, you can find the entropy values for the initial and final states, and then determine the total entropy production. Remember, in any spontaneous process, the entropy of the universe increases, making entropy production a key concept in understanding real-world thermodynamic processes.

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Most popular questions from this chapter

Answer the following true or false. If false, explain why. A process that violates the second law of thermodynamics violates the first law of thermodynamics. (b) When a net amount of work is done on a closed system undergoing an internally reversible process, a net heat transfer of energy from the system also occurs. (c) One corollary of the second law of thermodynamics states that the change in entropy of a closed system must be greater than zero or equal to zero. (d) A closed system can experience an increase in entropy only when irreversibilities are present within the system during the process. (e) Entropy is produced in every internally reversible process of a closed system. (f) In an adiabatic and internally reversible process of a closed system, the entropy remains constant. (g) The energy of an isolated system must remain constant, but the entropy can only decrease.

Taken together, a certain closed system and its surroundings make up an isolated system. Answer the following true or false. If false, explain why. (a) No process is allowed in which the entropies of both the system and the surroundings increase. (b) During a process, the entropy of the system might decrease, while the entropy of the surroundings increases, and conversely. (c) No process is allowed in which the entropies of both the system and the surroundings remain unchanged. (d) A process can occur in which the entropies of both the system and the surroundings decrease.

A patent application describes a device that at steady state receives a heat transfer at the rate 1 kW at a temperature of 167C and generates electricity. There are no other energy transfers. Does the claimed performance violate any principles of thermodynamics? Explain.

Air enters a compressor operating at steady state with a volumetric flow rate of 8 m3/min at 23C,0.12MPa. The air is compressed isothermally without internal irreversibilities, exiting at 1.5MPa. Kinetic and potential energy effects can be ignored. Evaluate the work required and the heat transfer, each in kW.

Air enters a compressor operating at steady state at 1 bar, 22C with a volumetric flow rate of 1 m3/min and is compressed to 4 bar, 177C. The power input is 3.5 kW. Employing the ideal gas model and ignoring kinetic and potential energy effects, obtain the following results: (a) For a control volume enclosing the compressor only, determine the heat transfer rate, in kW, and the change in specific entropy from inlet to exit, in kJ/kgK. What additional information would be required to evaluate the rate of entropy production? (b) Calculate the rate of entropy production, in kW/K, for an enlarged control volume enclosing the compressor and a portion of its immediate surroundings so that heat transfer occurs at the ambient temperature, 22C.

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