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The theoretical steam rate is the quantity of steam required to produce a unit amount of work in an ideal turbine. The Theoretical Steam Rate Tables published by The American Society of Mechanical Engineers give the theoretical steam rate in lb per \(\mathrm{kW} \cdot \mathrm{h}\). To determine the actual steam rate, the theoretical steam rate is divided by the isentropic turbine efficiency. Why is the steam rate a significant quantity? Discuss how the steam rate is used in practice.

Short Answer

Expert verified
The steam rate measures turbine efficiency and is key to estimating fuel consumption and operational costs.

Step by step solution

01

Understand the Theoretical Steam Rate

The theoretical steam rate is the steam required to produce one unit of work (1 kW·h) in an ideal turbine. This is given in pounds per kilowatt-hour (lb per \( \text{kW} \cdot \text{h} \)).
02

Calculate Actual Steam Rate

Actual steam rate is calculated by dividing the theoretical steam rate by the isentropic turbine efficiency. Mathematically: \[ \text{Actual Steam Rate} = \frac{\text{Theoretical Steam Rate}}{\text{Isentropic Turbine Efficiency}} \]
03

Significance of Steam Rate

The steam rate is significant because it measures the efficiency of the turbine. A lower steam rate means higher efficiency, indicating less steam is needed to produce a unit of work.
04

Practical Use of Steam Rate

In practice, the steam rate is used to estimate the fuel consumption and operational cost of a power plant. It helps in designing efficient turbines and optimizing the thermal efficiency of the power generation process.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Isentropic Turbine Efficiency
Isentropic turbine efficiency is a measure of how close a real turbine operates compared to an ideal turbine. Think of it like grading the turbine's performance. The more efficient the turbine, the closer it performs to an ideal, isentropic process.
The term 'isentropic' means a process that is both adiabatic (no heat transfer) and reversible. In simple terms, it refers to a perfect, lossless turbine. However, in the real world, every turbine has inefficiencies due to factors like friction and heat loss.
The efficiency of an isentropic turbine can be calculated using the formula:
\[ \text{Isentropic Efficiency} = \frac{\text{Actual Work Output}}{\text{Ideal Work Output}} \]
This formula compares the actual work the turbine does to the work it could do in an ideal scenario. Higher isentropic efficiency means the turbine is performing closer to this ideal.
Actual Steam Rate
The actual steam rate is an important metric in turbine performance analysis. It tells us how much steam is needed to produce one unit of work in real-world conditions, considering the turbine's actual performance.
To determine the actual steam rate, we use the following formula:
\[ \text{Actual Steam Rate} = \frac{\text{Theoretical Steam Rate}}{\text{Isentropic Turbine Efficiency}} \]
The theoretical steam rate assumes an ideal condition, where the turbine is perfectly efficient. However, the real-world scenario is different due to various inefficiencies.
By dividing the theoretical steam rate by the isentropic turbine efficiency, we get a realistic understanding of how much steam is required for the turbine to produce one unit of work. This actual steam rate helps in understanding and improving the overall efficiency of a power plant.
Thermal Efficiency
Thermal efficiency is a key concept in the context of turbines and power plants. It measures how well the turbine converts the energy in the steam into useful work.
In a simplified sense, thermal efficiency (\texteta_{thermal}) can be expressed as:
\[ \text{\texteta_{thermal}} = \frac{\text{Useful Output Energy}}{\text{Total Input Energy}} \]
This ratio gives us an idea of how much of the input energy (from fuel consumption) is effectively turned into output work. A higher thermal efficiency means that more of the input energy is effectively used, making the turbine more efficient.
Knowing the thermal efficiency helps engineers design better turbines and systems. It aids in optimizing the fuel use and reducing operational costs. This efficiency also has environmental benefits since higher efficiency typically means lower emissions per unit of produced electricity.

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Most popular questions from this chapter

The temperature of a 12 -oz \((0.354-\mathrm{L})\) can of soft drink is reduced from 20 to \(5^{\circ} \mathrm{C}\) by a refrigeration cycle. The cycle receives energy by heat transfer from the soft drink and discharges energy by heat transfer at \(20^{\circ} \mathrm{C}\) to the surroundings. There are no other heat transfers. Determine the minimum theoretical work input required by the cycle, in \(\mathrm{kJ}\), assuming the soft drink is an incompressible liquid with the properties of liquid water. Ignore the aluminum can.

Reducing irreversibilities within a system can improve its thermodynamic performance, but steps taken in this direction are usually constrained by other considerations. What are some of these?

Steam enters a horizontal \(15-\mathrm{cm}\)-diameter pipe as a saturated vapor at 5 bar with a velocity of \(10 \mathrm{~m} / \mathrm{s}\) and exits at \(4.5\) bar with a quality of \(95 \%\). Heat transfer from the pipe to the surroundings at \(300 \mathrm{~K}\) takes place at an average outer surface temperature of \(400 \mathrm{~K}\). For operation at steady state, determine (a) the velocity at the exit, in \(\mathrm{m} / \mathrm{s}\). (b) the rate of heat transfer from the pipe, in \(\mathrm{kW}\). (c) the rate of entropy production, in \(\mathrm{kW} / \mathrm{K}\), for a control volume comprising only the pipe and its contents. (d) the rate of entropy production, in \(\mathrm{kW} / \mathrm{K}\), for an enlarged control volume that includes the pipe and enough of its immediate surroundings so that heat transfer from the control volume occurs at \(300 \mathrm{~K}\). Why do the answers of parts (c) and (d) differ?

A piston-cylinder assembly initially contains \(0.1 \mathrm{~m}^{3}\) of carbon dioxide gas at \(0.3\) bar and \(400 \mathrm{~K}\). The gas is compressed isentropically to a state where the temperature is \(560 \mathrm{~K}\). Employing the ideal gas model and neglecting kinetic and potential energy effects, determine the final pressure, in bar, and the work in \(\mathrm{kJ}\), using (a) data from Table A-23. (b) \(I T\) (c) a constant specific heat ratio from Table A-20 at the mean temperature, \(480 \mathrm{~K}\). (d) a constant specific heat ratio from Table A-20 at \(300 \mathrm{~K}\).

Water vapor enters an insulated nozzle operating at steady state at \(0.7 \mathrm{MPa}, 320^{\circ} \mathrm{C}, 35 \mathrm{~m} / \mathrm{s}\) and expands to \(0.15 \mathrm{MPa}\). If the isentropic nozzle efficiency is \(94 \%\), determine the velocity at the exit, in \(\mathrm{m} / \mathrm{s}\).

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