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Using the tables for water, determine the specified property data at the indicated states. Check the results using IT. In each case, locate the state by hand on sketches of the pv and Tv diagrams. (a) At p=3 bar, T=240C, find v in m3/kg and u in kJ/kg. (b) At p=3 bar, v=0.5 m3/kg, find T in C and u in kJ/kg. (c) At T=400C,p=10 bar, find v in m3/kg and h in kJ/kg. (d) At T=320C,v=0.03 m3/kg, find p in MPa and u in kJ/kg (e) At p=28MPa,T=520C, find v in m3/kg and h in kJ/kg. (f) At T=100C,x=60%, find p in bar and v in m3/kg. (g) At T=10C,v=100 m3/kg, find p in kPa and h in kJ/kg. (h) At p=4MPa,T=160C, find v in m3/kg and u in kJ/kg.

Short Answer

Expert verified
Use steam tables to locate property data for each state based on provided conditions and sketch the state in the relevant diagrams.

Step by step solution

01

Find specific volume and internal energy at given pressure and temperature

Given: \ Pressure, p=3 bar=300 kPa \ Temperature, T=240C \ Using water property tables, locate the data for the given conditions. If the conditions fall under the superheated region, use the superheated steam tables to find specific volume (v) and internal energy (u).
02

Verify the state and locate on diagrams

Check the pressure and temperature against the saturation properties. Since T>Tsat, the state is superheated. Sketch the state on the pv and Tv diagrams.
03

Find temperature and internal energy at given pressure and specific volume

Given: \ Pressure, p=3 bar=300 kPa \ Specific Volume, v=0.5 m3/kg \ Use the water property tables to find the corresponding temperature (T) and internal energy (u).
04

Verify the state and locate on diagrams

Compare the given v with values in the tables. If vf<v<vg, the state is in the vapor dome (mixture). If v>vg, the state is superheated. Sketch the state on the pv and Tv diagrams.
05

Determine specific volume and enthalpy at given conditions

Given: \ Temperature, T=400C \ Pressure, p=10 bar=1000 kPa \ Use the superheated steam tables to find specific volume (v) and enthalpy (h).
06

Verify the state and locate on diagrams

Sketch the state on the pv and Tv diagrams after verifying that the conditions are in the superheated region.
07

Find pressure and internal energy at given temperature and specific volume

Given: \ Temperature, T=320C \ Specific Volume, v=0.03 m3/kg \ Use the water property tables to find the corresponding pressure (p) and internal energy (u).
08

Verify the state and locate on diagrams

Compare v with the saturation values. If vf<v<vg, the state is a mixture. If v>vg, the state is superheated. Sketch the state on the pv and Tv diagrams.
09

Determine specific volume and enthalpy at given pressure and temperature

Given: \ Pressure, p=28 MPa \ Temperature, T=520C \ Use the supercritical steam tables to find specific volume (v) and enthalpy (h).
10

Verify the state and locate on diagrams

Sketch the state on the pv and Tv diagrams after confirming the supercritical conditions.
11

Find pressure and specific volume at given temperature and dryness fraction

Given: \ Temperature, T=100C \ Quality, x=0.6 \ Use the saturation tables to find the corresponding pressure (p) and specific volumes (vf and vfg). Calculate specific volume (v) using v=vf+xvfg.
12

Verify the state and locate on diagrams

Sketch the state (saturated mixture) on the pv and Tv diagrams.
13

Determine pressure and enthalpy at given temperature and specific volume

Given: \ Temperature, T=10C \ Specific Volume, v=100 m3/kg \ Use the water property tables to find the corresponding pressure (p) and enthalpy (h).
14

Verify the state and locate on diagrams

Identify the region comparing v with the table values. Sketch the state on the pv and Tv diagrams.
15

Find specific volume and internal energy at given pressure and temperature

Given: \ Pressure, p=4 MPa \ Temperature, T=160C \ Use the water property tables to find specific volume (v) and internal energy (u).
16

Verify the state and locate on diagrams

Sketch the state on the pv and Tv diagrams after verifying the conditions specified.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Specific volume in Thermodynamics
Specific volume is a key property in thermodynamics that represents the volume occupied by a unit mass of a substance. In simpler terms, it is the reciprocal of density. Specific volume (v) is given by the formula: v=VmWhere V is the volume and m is the mass. Think of it this way: if you have a larger specific volume, it means each kilogram of the substance takes up more space. This is particularly important in steam and gas calculations. The typical units for specific volume are m3/kg. If you're using water property tables, you often need to check whether the conditions fall under compressed liquid, saturated, or superheated vapor states. To determine the specific volume for given states like in the exercise, navigate through the steam tables or use software tools designed for property calculations.
Understanding Internal Energy
Internal energy (u) represents the total energy related to the molecular structure of a substance, including kinetic and potential energies at the molecular level. It is a key concept in the first law of thermodynamics, where changes in internal energy are connected to heat transfer and work done. For instance, in the exercise, internal energy was to be found for various states like at pressures of 3 bar and temperatures of 240°C. To find this, specific internal energy data can be derived from the steam tables for water. Internal energy values are typically expressed in kJ/kg. Knowing internal energy helps in understanding heat interactions and work potential of a system. Keep in mind that internal energy changes based on whether a substance is in the liquid phase, vapor phase, or mixture.
Enthalpy in Thermodynamics
Enthalpy (h) is another vital thermodynamic property that encompasses the total heat content of a system. It is defined as the sum of internal energy and the product of pressure and volume: h=u+pvEnthalpy is particularly useful in processes involving heat transfer under constant pressure, such as phase changes from liquid to gas. In the exercise, finding enthalpy at conditions like 400°C and 10 bar involves looking up superheated steam tables. The values are generally given in kJ/kg. Understanding enthalpy allows us to analyze energy exchanges during thermodynamic cycles and different states. For a given temperature and pressure, you can use specialized tables to locate the enthalpy directly or calculate it based on internal energy and specific volume.

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Most popular questions from this chapter

Natural Refrigerants-Back to the Future (see box Sec. 3.3). Although used for home appliances in Europe, hydrocarbon refrigerants have not taken hold in the United States thus far owing to concerns about liability if there is an accident. Research hydrocarbon refrigerant safety. Write a report including at least three references.

Steam is contained in a closed rigid container with a volume of 1 m3. Initially, the pressure and temperature of the steam are 7 bar and 500C, respectively. The temperature drops as a result of heat transfer to the surroundings. Determine the temperature at which condensation first occurs, in C, and the fraction of the total mass that has condensed when the pressure reaches 0.5 bar. What is the volume, in m3, occupied by saturated liquid at the final state?

A two-phase liquid-vapor mixture of H2O, initially at 1.0 MPa with a quality of 90%, is contained in a rigid, wellinsulated tank. The mass of H2O is 2 kg. An electric resistance heater in the tank transfers energy to the water at a constant rate of 60 W for 1.95 h. Determine the final temperature of the water in the tank, in C.

Consider a gas mixture whose apparent molecular weight is 33 , initially at 3 bar and 300 K, and occupying a volume of 0.1 m3. The gas undergoes an expansion during which the pressure-volume relation is pV1.3= constant and the energy transfer by heat to the gas is 3.84 kJ. Assume the ideal gas model with cv=0.6+(2.5×104)T, where T is in K and cv has units of kJ/kgK. Neglecting kinetic and potential energy effects, determine (a) the final temperature, in K. (b) the final pressure, in bar. (c) the final volume, in m3. (d) the work, in kJ.

A gas is confined to one side of a rigid, insulated container divided by a partition. The other side is initially evacuated. The following data are known for the initial state of the gas: p1=5 bar, T1=500 K, and V1=0.2 m3. When the partition is removed, the gas expands to fill the entire container, which has a total volume of 0.5 m3. Assuming ideal gas behavior, determine the final pressure, in bar.

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