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. Under what circumstances is the following statement correct? Equal molar amounts of two different gases at the same temperature, placed in containers of equal volume, have the same pressure.

Short Answer

Expert verified
Equal pressures when molar amount, temperature, and volume are the same.

Step by step solution

01

- Understand the Ideal Gas Law

The Ideal Gas Law states: \[ PV = nRT \]Where:- \(P\) is the pressure,- \(V\) is the volume,- \(n\) is the number of moles,- \(R\) is the universal gas constant,- \(T\) is the temperature.
02

- Analyzing the Given Conditions

Given that the gases have equal molar amounts (i.e., the same number of moles, \(n\)) and are at the same temperature (\(T\)). They are also placed in containers of equal volume (\(V\)).
03

- Applying the Ideal Gas Law to Each Container

For the first gas, the pressure can be expressed as:\[ P_1V = nRT \]For the second gas, the pressure can be expressed as:\[ P_2V = nRT \]Since \(V\), \(n\), \(R\), and \(T\) are the same for both gases, the pressures \(P_1\) and \(P_2\) must also be equal.
04

- Conclusion

Under the conditions that all other variables (molar amount, temperature, volume, and the gas constant) are the same, the pressures of the two gases will be equal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Pressure
Pressure is a force exerted by gas particles when they collide with the walls of their container. In the context of the Ideal Gas Law, it's denoted by the symbol \(P\). Pressure is crucial because it tells us how much force gas particles are applying. In daily life, we measure pressure in different units like atmospheres (atm), pascals (Pa), or pounds per square inch (psi). Higher pressure means particles collide more frequently and forcefully against the container walls.
Defining Volume
Volume (\(V\)) is the amount of space a gas occupies. In the Ideal Gas Law, volume is crucial as it helps to determine how much space gas particles have to move around. The volume of a gas can be measured in liters (L), cubic meters (m³), or cubic centimeters (cm³). Different volumes under constant temperature and pressure will hold different amounts of gas. In our exercise, the volume is the same for both gases, meaning they have the same amount of space to move around.
Exploring Moles
A mole (\(n\)) is a measurement of the amount of substance and is part of the Ideal Gas Law. One mole contains approximately 6.022 \times 10^{23} particles (Avogadro's number). It's a way to count atoms or molecules. In our scenario, equal molar amounts mean both containers have the same number of gas molecules. This is why the pressure relates directly to the number of moles when temperature and volume remain constant.
The Universal Gas Constant
The universal gas constant (\(R\)) is a constant that appears in the Ideal Gas Law. Its value is approximately 8.314 J/(mol·K). \(R\) provides a relationship factor between the pressure, volume, moles, and temperature of a gas. It helps unify these variables into one equation. Different units of \(R\) are used depending on the units of pressure and volume in a given context. For instance, it's essential when calculating how gases behave under varying conditions.
Importance of Temperature
Temperature (\(T\)) is a measure of the average kinetic energy of gas particles. In the Ideal Gas Law, it's expressed in Kelvin. It directly influences the behavior of gases. Higher temperatures mean gas particles move more energetically, increasing pressure if volume and the number of moles remain constant. In the exercise, both gases are at the same temperature, ensuring they have equivalent kinetic energy. This consistency helps in concluding that pressures remain equal when other factors are constant.

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Most popular questions from this chapter

Determine the temperature, in \(\mathrm{K}\), of \(5 \mathrm{~kg}\) of air at a pressure of \(0.3 \mathrm{MPa}\) and a volume of \(2.2 \mathrm{~m}^{3} .\) Verify that ideal gas behavior can be assumed for air under these conditions.

A piston-cylinder assembly contains \(1 \mathrm{~kg}\) of nitrogen gas \(\left(\mathrm{N}_{2}\right)\). The gas expands from an initial state where \(T_{1}=700 \mathrm{~K}\) and \(p_{1}=5\) bar to a final state where \(p_{2}=2\) bar. During the process the pressure and specific volume are related by \(p v^{1.3}=\) constant. Assuming ideal gas behavior and neglecting kinetic and potential energy effects, determine the heat transfer during the process, in \(\mathrm{kJ}\), using (a) a constant specific heat evaluated at \(300 \mathrm{~K}\). (b) a constant specific heat evaluated at \(700 \mathrm{~K}\). (c) data from Table A-23.

A system consists of \(2 \mathrm{~kg}\) of carbon dioxide gas initially at, state 1 , where \(p_{1}=1\) bar, \(T_{1}=300 \mathrm{~K}\). The system undergoes a power cycle consisting of the following processes: Process 1-2: constant volume to \(p_{2}, p_{2}>p_{1}\) Process 2-3: expansion with \(p v^{1.28}=\) constant Process 3-1: constant-pressure compression Assuming the ideal gas model and neglecting kinetic and potential energy effects, (a) sketch the cycle on a \(p-v\) diagram. (b) plot the thermal efficiency versus \(p_{2} / p_{1}\) ranging from \(1.05\) to 4 .

Why does food cook more quickly in a pressure cooker than in water boiling in an open container?

One kilogram of saturated solid water at the triple point is heated to saturated liquid while the pressure is maintained constant. Determine the work and the heat transfer for the process, each in \(\mathrm{kJ}\). Show that the heat transfer equals the change in enthalpy of the water in this case.

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