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Air at 30C,1 bar, 50% relative humidity enters an insulated chamber operating at steady state with a mass flow rate of 3 kg/min and mixes with a saturated moist air stream entering at 5C,1 bar with a mass flow rate of 5 kg/min. A single mixed stream exits at 1 bar. Determine (a) the relative humidity and temperature, in C, of the exiting stream. (b) the rate of exergy destruction, in kW, for T0=20C. Neglect kinetic and potential energy effects.

Short Answer

Expert verified
Exit stream: Find mass and energy balances and properties from psychrometric tables for exit RH and temperature. Exergy destruction: Calculate using exergy balance equation.

Step by step solution

01

- Determine Saturation Properties

Use psychrometric tables to find the saturation pressures and other related properties for the given temperatures. For 30°C and 5°C, find the saturation pressure.
02

- Calculate Partial Pressures

Using the relative humidity and the saturation pressures, calculate the partial pressures of water vapor in each entering stream. For the 30°C, 50% RH stream: Pws,30=Psat@30°CPv1=0.5Pws,30For the 5°C, saturated stream:Pv2=Psat@5°C
03

- Calculate Mass Flow Rate of Dry Air

Calculate the mass flow rates of dry air for each stream. Assuming ideal gas law for air-water vapor mixture and given mass flow rates, calculate using:mdry,1mtotal,1=Pdry,1Ptotal\where Pdry,1=PtotalPv1.
04

- Write the Mass and Energy Balance Equations

Formulate and solve mass and energy balance equations for the mixing process at steady state to find the properties of the exit stream.
05

- Determine Exit Properties

Calculate the exit temperature using the energy balance equation and find the exit relative humidity using the saturation properties at the exit temperature.
06

- Calculate Exergy Destruction

Using the exit properties and the inlet properties, calculate the exergy destruction rate. This can be done through the exergy balance: Exergy destruction=(mtotal,exit×eex,exit)(m1×eex,1)(m2×eex,2) where e_{ex} denotes specific exergy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Psychrometric Properties
Psychrometric properties of air-water vapor mixtures are crucial in thermodynamics, particularly in processes involving humid air. These properties include temperature, pressure, humidity, enthalpy, and specific volume.
To solve the exercise, we began by determining the saturation pressures at the given temperatures of 30°C and 5°C. Saturation pressure is the maximum pressure that water vapor can exert at a particular temperature when the air is in equilibrium with liquid water. These values are typically found in psychrometric tables.
The next step involved calculating the partial pressures of water vapor in each stream. The relative humidity (RH) indicates how close the air is to being saturated with water vapor. It's calculated using the equation:
RH=100×PvPws
where Pv is the partial pressure of water vapor, and Pws is the saturation pressure at the given temperature.
Mass Balance Equations
The mass balance equation is foundational in determining the exit properties of the mixed stream. It ensures that the total mass entering a system is equal to the total mass leaving it. In this exercise, we need to account for both the dry air and water vapor components.
For dry air, we calculate the mass flow rates using the ideal gas law. For each stream: mdrymtotal=PdryPtotal
Here, Pdry is the partial pressure of dry air, calculated by subtracting the partial pressure of water vapor from the total pressure.
By writing an overall mass balance for dry air and water vapor separately, we ensure that mass is conserved. This step is vital for pinpointing the exact composition of the exit stream.
Energy Balance Equations
Energy balance equations help us find the exit temperature of the mixed stream. These equations state that the total energy entering a system must equal the total energy leaving it. In this mix, we focus on the enthalpy changes.
Writing the energy balance equation for steady-state conditions (neglecting kinetic and potential energies), we get:
m1h1+m2h2=mexithexit
Where m denotes the mass flow rate, and h represents the specific enthalpy of the air-water vapor mixture. By solving this equation, we determine the exit temperature and use it in conjunction with the saturation data to find the exit humidity.
Exergy Destruction
Exergy destruction represents the loss of potential to perform useful work during a process. This is significant in evaluating the efficiency of thermodynamic systems.
The exergy balance equation for this exercise is:
Exergy destruction=(mexit×eex,exit)(m1×eex,1)(m2×eex,2)
Here, eex stands for specific exergy. To find the exergy destruction, we use the properties calculated from previous steps and the exit stream specifics. Exergy analysis helps in optimizing processes by pinpointing where energy losses occur.
Relative Humidity Calculation
Relative Humidity (RH) plays a critical role in psychrometric processes. It's a measure of how much water vapor is present in the air relative to the maximum amount air can hold at that temperature.
To calculate RH for the exit stream, we use the saturation properties at the exit temperature. The formula is:
RH=100×PvPws
Where Pv is the actual partial pressure of water vapor in the air, and Pws is the saturation pressure at the exit temperature. This calculation ensures that we understand the moisture content of the exiting air.
Saturation Properties
Saturation properties are essential in defining the state of air-water vapor mixtures. They include parameters like saturation pressure, specific enthalpy, and specific volume corresponding to a particular temperature.
For this exercise, we used thermodynamic tables to find the saturation pressure at both 30°C and 5°C. These pressures serve as reference points to calculate partial pressures and help in understanding the extent of air saturation.
Knowing the saturation properties allows us to accurately perform relative humidity and energy balance calculations, ensuring we can quantify the conditions of the exit stream accurately.

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Most popular questions from this chapter

Figure P12.5D shows a system for supplying a space with 2100 m3/min of conditioned air at a dry-bulb temperature of 22C and a relative humidity of 60% when the outside air is at a dry-bulb temperature of 35C and a relative humidity of 55%. Dampers A and B can be set to give three alternative operating modes: (1) Both dampers closed (no use of recirculated air). (2) Damper A open and damper B closed. One-third of the conditioned air comes from outside air. (3) Both dampers open. One-third of the conditioned air comes from outside air. One- third of the recirculated air bypasses the dehumidifier via open damper B, and the rest flows through the damper A. Which of the three operating modes should be used? Discuss.

Using the ideal gas model with constant specific heats, determine the mixture temperature, in K, for each of two cases: (a) Initially, 0.6kmol of O2 at 500 K is separated by a partition from 0.4kmol of H2 at 300 K in a rigid insulated vessel. The partition is removed and the gases mix to obtain a final equilibrium state. (b) Oxygen (O2) at 500 K and a molar flow rate of 0.6kmol/s enters an insulated control volume operating at steady state and mixes with H2 entering as a separate stream at 300 K and a molar flow rate of 0.4kmol/s. A single mixed stream exits. Kinetic and potential energy effects can be ignored.

Liquid water at 50C enters a forced draft cooling tower operating at steady state. Cooled water exits the tower with a mass flow rate of 80 kg/min. No makeup water is provided. A fan located within the tower draws in atmospheric air at 17C, 0.098MPa,60% relative humidity with a volumetric flow rate of 110 m3/min. Saturated air exits the tower at 30C,0.098 MPa. The power input to the fan is 8 kW. Ignoring kinetic and potential energy effects, determine (a) the mass flow rate of the liquid stream entering, in kg/min. (b) the temperature of the cooled liquid stream exiting, in C.

Air at 35C,1 bar, and 10% relative humidity enters an evaporative cooler operating at steady state. The volumetric flow rate of the incoming air is 50 m3/min. Liquid water at 20C enters the cooler and fully evaporates. Moist air exits the cooler at 25C,1 bar. If there is no significant heat transfer between the device and its surroundings, determine (a) the rate at which liquid enters, in kg/min. (b) the relative humidity at the exit. (c) the rate of exergy destruction, in kJ/min, for T0=20C. Neglect kinetic and potential energy effects.

At steady state, moist air is to be supplied to a classroom at a specified volumetric flow rate and temperature T. Air is removed from the classroom in a separate stream at a temperature of 27C and 50% relative humidity. Moisture is added to the air in the room from the occupants at a rate of 4.5 kg/h. The moisturc can be regardcd as saturated vapor at 33C. Hcat transfer into the occupied space from all sources is estimated to occur at a rate of 34,000 kJ/h. The pressure remains uniform at 1 atm. (a) For a supply air volumetric flow rate of 40 m3/min, determine the supply air temperature T, in C, and the relative humidity. (b) Plot the supply air temperature, in C, and relative humidity, each versus the supply air volumetric flow rate ranging from 35 to 90 m3/min.

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