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Why does your bathroom mirror often fog up when you shower?

Short Answer

Expert verified
The mirror fogs up due to condensation of water vapor from the shower on the cooler mirror surface.

Step by step solution

01

Understand the Source of Moisture

When you take a hot shower, the water vapor that comes from the hot water increases the humidity in the bathroom.
02

Explain Condensation

Condensation occurs when water vapor in the air turns into liquid water. This happens when the water vapor comes into contact with a cooler surface, like a mirror.
03

Cold Surface Interaction

The mirror in the bathroom is typically cooler than the surrounding air. The warm, moist air from the shower comes into contact with the cooler surface of the mirror, causing the water vapor to condense into tiny water droplets.
04

Resulting Fog

These tiny water droplets form a thin layer on the surface of the mirror, which scatters light and creates the appearance of fog. This is why the mirror looks foggy after a hot shower.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Humidity
Humidity refers to the amount of water vapor present in the air. When you take a hot shower, the steam you see is water vapor, which increases the humidity level in the bathroom. As more and more steam fills the room, the air becomes saturated with moisture. This is why it feels warm and damp inside the bathroom during and after a shower. The high humidity level is a key factor for the next stages of condensation to happen.
Water Vapor
Water vapor is water in its gas state. When you take a hot shower, the heat converts liquid water into water vapor, creating steam. This steam mixes with the air in the bathroom, increasing the air's water vapor content. Once the bathroom's air is full of water vapor, it seeks out cooler surfaces to cling to. This transition from hot steam to liquid droplets on a cooler surface is what sets the stage for condensation.
Cooler Surfaces
Cooler surfaces like mirrors, windows, and tiles become ideal spots for condensation. In the bathroom, the mirror is usually cooler than the surrounding air and steam. When the warm, humid air makes contact with the cooler mirror surface, the temperature drop causes the water vapor to turn back into liquid water. This process, called condensation, results in tiny water droplets forming on the mirror. This is why the mirror fogs up after a shower.
Foggy Mirrors
When water vapor condenses on a cooler surface like a bathroom mirror, it forms tiny water droplets. These droplets scatter light and create a foggy appearance. Foggy mirrors are a common occurrence in bathrooms after hot showers. To prevent this, you can use anti-fog sprays or keep the bathroom ventilated. Opening a window or using an exhaust fan helps move the humid air out, reducing the amount of condensation on the mirror.

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Most popular questions from this chapter

A stream consisting of \(35 \mathrm{~m}^{3} / \mathrm{min}\) of moist air at \(14^{\circ} \mathrm{C}\), \(1 \mathrm{~atm}, 80 \%\) relative humidity mixes adiabatically with a stream consisting of \(80 \mathrm{~m}^{3} / \mathrm{min}\) of moist air at \(40^{\circ} \mathrm{C}, 1 \mathrm{~atm}\), \(40 \%\) relative humidity, giving a single mixed stream at \(1 \mathrm{~atm}\). Using the psychrometric chart together with the procedure of Prob. 12.58, determine the relative humidity and temperature, in \({ }^{\circ} \mathrm{C}\), of the exiting stream.

A system consists initially of \(n_{\mathrm{A}}\) moles of gas \(\mathrm{A}\) at pressure \(p\) and temperature \(T\) and \(n_{\mathrm{B}}\) moles of gas B separate from gas A but at the same pressure and temperature. The gases are allowed to mix with no heat or work interactions with the surroundings. The final equilibrium pressure and temperature are \(p\) and \(T\), respectively, and the mixing occurs with no change in total volume. (a) Assuming ideal gas behavior, obtain an expression for the entropy produced in terms of \(\bar{R}, n_{\mathrm{A}}\), and \(n_{\mathrm{B}}\) (b) Using the result of part (a), demonstrate that the entropy produced has a positive value. (c) Would entropy be produced when samples of the same gas at the same temperature and pressure mix? Explain.

Air at \(35^{\circ} \mathrm{C}, 3\) bar, \(30 \%\) relative humidity, and a velocity of \(50 \mathrm{~m} / \mathrm{s}\) expands isentropically through a nozzle. Determine the lowest exit pressure, in bar, that can be attained without condensation. For this exit pressure, determine the exit velocity, in \(\mathrm{m} / \mathrm{s}\). The nozzle operates at steady state and without significant potential energy effects.

Air at \(77^{\circ} \mathrm{C}, 1\) bar, and a molar flow rate of \(0.1 \mathrm{kmol} / \mathrm{s}\) enters an insulated mixing chamber operating at steady state and mixes with water vapor entering at \(277^{\circ} \mathrm{C}, 1\) bar, and a molar flow rate of \(0.3 \mathrm{kmol} / \mathrm{s}\). The mixture exits at 1 bar. Kinetic and potential energy effects can be ignored. For the chamber, determine (a) the temperature of the exiting mixture, in \({ }^{\circ} \mathrm{C}\). (b) the rate of entropy production, in \(\mathrm{kW} / \mathrm{K}\).

Answer the following questions involving a mixture of two gases: (a) When would the analysis of the mixture in terms of mass fractions be identical to the analysis in terms of mole fractions? (b) When would the apparent molecular weight of the mixture equal the average of the molecular weights of the two gases?

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