Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Methane enters a turbine operating at steady state at 100 bar, \(275 \mathrm{~K}\) and expands isothermally without irreversibilities to 15 bar. There are no significant changes in kinetic or potential energy. Using data from the generalized fugacity and enthalpy departure charts, determine the power developed and heat transfer, each in \(\mathrm{kW}\), for a mass flow rate of \(0.5 \mathrm{~kg} / \mathrm{s}\)

Short Answer

Expert verified
The power developed and the heat transfer are determined by using generalized charts and the properties of methane for the isothermal expansion process.

Step by step solution

01

Identify Initial Conditions

Methane enters at 100 bar and 275 K. The process is isothermal (temperature remains constant) and reaches 15 bar.
02

Isothermal Process Definition

For an isothermal process, the temperature stays constant. Heat transfer and work are related by the equation: \[ Q = -W \]
03

Generalized Fugacity and Enthalpy Departure

Use generalized charts for fugacity and enthalpy departure to determine properties at different states. Read fugacity coefficients for methane at both 100 bar and 15 bar at 275 K.
04

Calculate the Work Done by the Turbine

The work done in an isothermal irreversible expansion can be calculated by:\[ W = RT \frac{dF}{F} \]
05

Power Developed

Using the mass flow rate, convert the work done per unit mass to power: \[ Power (kW) = Work (\frac{kJ}{kg}) \times mass flow (\frac{kg}{s}) \]
06

Calculate the Heat Transfer

The heat transfer in an isothermal process is equal and opposite to the work done: \[ Q = -W \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Isothermal Process
In an isothermal process, the temperature remains constant throughout the entire process. For our specific case with methane, this means that the temperature stays at 275 K as it expands from 100 bar to 15 bar. Since the temperature does not change, the internal energy change \( \Delta U \) will be zero for an ideal gas.

A key feature in isothermal processes is the relationship between heat (Q) and work (W). According to the first law of thermodynamics, for our steady-state system, this relationship is given by:

\[ Q = -W \]
In other words, the heat added to the system is equal and opposite to the work done by the system. This easy-to-understand relationship is particularly important for calculating heat transfer and work in our specific turbine problem.
Turbine Calculations
The turbine in this problem is expanding methane isothermally and without irreversibilities, meaning it is an idealized process. To find the work done by the turbine, we first need to identify the properties of methane at both starting and ending conditions—100 bar and 275 K to 15 bar and 275 K.

The work done by the turbine in an isothermal process can be determined using:
\[ W = RT \frac{dF}{F} \]
R is the universal gas constant, T is the temperature (275 K), and dF/F is the differential change in fugacity coefficients.

After calculating the work done per unit mass, the power can be calculated using the mass flow rate:
\[ Power (\text{kW}) = Work (\frac{kJ}{kg}) \times mass\ flow\ (\frac{kg}{s}) \]
This formula allows the conversion of the work into kilowatts, essential for practical applications.
Generalized Fugacity Charts
Fugacity is an adjusted pressure that helps account for deviations from ideal gas behavior. Fugacity coefficients are factors derived from generalized fugacity charts that make it easier to find the properties of any gas at different states.

For methane, you will read the fugacity coefficients at 100 bar and 15 bar at the constant temperature of 275 K. These coefficients help us in calculating the difference in fugacity (dF/F), which can then be used in the formula for work done by the turbine.

Using fugacity makes calculations more accurate when dealing with real gases, ensuring our thermodynamic predictions align closely with real-world behavior.
Enthalpy Departure Charts
Enthalpy departure is the difference between the real gas enthalpy and the ideal gas enthalpy at the same temperature and pressure. Enthalpy departure charts provide quick access to these values for different gases and states.

In this exercise, you use the enthalpy departure values to correct the ideal gas property calculations, aligning them closer with the real gas behavior of methane. These corrections are necessary because real gases exhibit interactions between molecules and non-ideal behavior, aspects that ideal gas laws do not account for.

By consulting enthalpy departure charts, you ensure that your calculations for heat transfer and work are more accurate and reflective of the actual physical process happening within the turbine.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

To investigate liquid-vapor phase transition behavior, construct a \(p-v\) diagram for water showing isotherms in the range \(0.7

Air having an approximate molar composition of \(79 \%\) \(\mathrm{N}_{2}\) and \(21 \% \mathrm{O}_{2}\) fills a \(0.36-\mathrm{m}^{3}\) vessel. The mass of mixture is \(100 \mathrm{~kg}\). The measured pressure and temperature are 101 bar and \(180 \mathrm{~K}\), respectively. Compare the measured pressure with the pressure predicted using (a) the ideal gas equation of state. (b) Kay's rule. (c) the additive pressure rule with the Redlich-Kwong equation. (d) the additive volume rule with the Redlich-Kwong equation.

The volume of a \(1-\mathrm{kg}\) copper sphere is not allowed to vary by more than \(0.1 \%\). If the pressure exerted on the sphere is increased from 10 bar while the temperature remains constant at \(300 \mathrm{~K}\), determine the maximum allowed pressure, in bar. Average values of \(\rho, \beta\), and \(\kappa\) are \(8888 \mathrm{~kg} / \mathrm{m}^{3}, 49.2 \times 10^{-6}\) \((\mathrm{K})^{-1}\), and \(0.776 \times 10^{-11} \mathrm{~m}^{2} / \mathrm{N}\), respectively.

Nitrogen \(\left(\mathrm{N}_{2}\right)\) enters a compressor operating at steady state at \(1.5 \mathrm{MPa}, 300 \mathrm{~K}\) and exits at \(8 \mathrm{MPa}, 500 \mathrm{~K}\). If the work input is \(240 \mathrm{~kJ}\) per \(\mathrm{kg}\) of nitrogen flowing, determine the heat transfer, in kJ per \(\mathrm{kg}\) of nitrogen flowing. Ignore kinetic and potential energy effects.

Derive an equation for the Joule-Thomson coefficient as a function of \(T\) and \(v\) for a gas that obeys the van der Waals equation of state and whose specific heat \(c_{v}\) is given by \(c_{v}=\) \(A+B T+C T^{2}\), where \(A, B, C\) are constants. Evaluate the temperatures at the inversion states in terms of \(R, v\), and the van der Waals constants \(a\) and \(b\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free