Chapter 11: Problem 37
The \(p-v-T\) relation for a certain gas is represented closely by \(v=R T / p+B-A / R T\), where \(R\) is the gas constant and \(A\) and \(B\) are constants. Determine expressions for the changes in specific enthalpy, internal energy, and entropy, \(\left[h\left(p_{2}, T\right)-\right.\) \(\left.h\left(p_{1}, T\right)\right],\left[u\left(p_{2}, T\right)-u\left(p_{1}, T\right)\right]\), and \(\left[s\left(p_{2}, T\right)-s\left(p_{1}, T\right)\right]\) respectively.
Short Answer
Step by step solution
Understanding the given relation
Writing the enthalpy change equation
Simplifying enthalpy change
Writing the internal energy change equation
Simplifying internal energy change
Writing the entropy change equation
Simplifying entropy change
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
p-v-T relation
- v is the specific volume
- R is the gas constant
- T is the temperature
- p is the pressure
- A and B are constants
specific enthalpy change
internal energy change
entropy change
thermodynamic equations
- p-v-T relation: \[ v = \frac{R T}{p} + B - \frac{A}{R T} \]
- Enthalpy change: \[ \Delta h = (u_2 - u_1) + (p_2 - p_1)B - \frac{A}{R T} (p_2 - p_1) \]
- Internal energy change: \[ \Delta u = 0 \] under isothermal conditions
- Entropy change: \[ \Delta s = -R \ln \left( \frac{p_2}{p_1} \right) \]