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Two circular wire rings are parallel to each other, share the same axis, are of radius a, and are separated by distance d, where \(d<

Short Answer

Expert verified
Answer: The approximate force of attraction between the two wire rings is given by F=μ0I2a2d(a2+d2)2. The relative orientation of the currents should be in the same direction (either clockwise or counterclockwise for both rings) for the rings to attract each other.

Step by step solution

01

Determine the magnetic field produced by a circular wire ring

Given that each wire ring has a radius "a" and carries a current "I", we can use Ampere's Law to determine the magnetic field produced by one ring. The magnetic field at a distance "d" above the center of the ring can be determined using the equation: B=μ0Ia22(a2+d2)3/2
02

Determine the force between the two rings

The force between the two rings can be determined using the equation: F=I1I2C1C2μ0ddl1dl24π(a2+d2)2 Since both rings have the same current "I" and we are assuming a constant magnetic field, we can simplify the equation as: F=I2C1C2μ0ddl1dl24π(a2+d2)2
03

Evaluate the double integral

To find the force, we need to evaluate the double integral in the equation: F=I2C1C2μ0ddl1dl24π(a2+d2)2=I2μ0dC1C2dl1dl24π(a2+d2)2 Since the rings are parallel to each other, we can use their symmetry to further simplify this expression: F=I2μ0dL1L24π(a2+d2)2 Where L1 and L2 represent the lengths of the perimeters of the rings. Since both rings have the same radius, their perimeters are equal, and we can write: F=I2μ0d2πa2πa4π(a2+d2)2
04

Compute the force of attraction

Simplify the expression and find the force of attraction between the two rings: F=I2μ0d4π2a24π(a2+d2)2=μ0I2a2d(a2+d2)2
05

Determine the relative orientations of the currents

To attract each other, the circular wire rings should have currents flowing in the same direction. Their magnetic fields will interact, leading to an attractive force between the rings. Thus, the relative orientation of the currents should be in the same direction (either clockwise or counterclockwise for both rings) for them to experience an attraction force. In conclusion, the approximate force of attraction between the two wire rings is given by: F=μ0I2a2d(a2+d2)2 And the relative orientation of the currents should be in the same direction for the rings to attract each other.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ampere's Law
Ampere's Law is a fundamental principle in electromagnetism that relates the integrated magnetic field around a closed loop to the electric current passing through the loop. It is expressed mathematically as Bdl=μ0Ienclosed, where B is the magnetic field, dl is a differential length element of the loop, and Ienclosed is the current enclosed by the loop. This law helps us calculate magnetic fields created by current-carrying conductors.
In the exercise, we use Ampere's Law to determine the magnetic field produced by a ring of current at a point along its axis. By symmetry and simplification, we find that the magnetic field at distance "d" from the center of a ring is given by B=μ0Ia22(a2+d2)3/2. This equation comes from the Biot-Savart law under certain symmetric conditions, where μ0 is the permeability of free space, and a and d are the radius of the ring and the distance from the ring center, respectively.
Force of Attraction
The force of attraction between two circular wire rings is derived from the interaction of their magnetic fields. Each ring produces a magnetic field due to the flow of current. When these fields interact, they can create forces that either attract or repel depending on the direction of the currents.
In this exercise, we use simplified equations to calculate the force of attraction. The derived expression F=μ0I2a2d(a2+d2)2 shows how the force changes with different parameters: the current I, the separation d, and the radius a of the rings.
The force is proportional to the square of the current and the separation distance but inversely proportional to the fourth power of the sum of the squares of the radius and the separation distance. This reveals how sensitive the attraction is to distance and current strength.
Current Orientation
The orientation of currents in the two rings plays a crucial role in determining whether they attract or repel each other. If the currents flow in the same direction around both rings, their magnetic fields will align in such a way that a force of attraction is generated.
This can be understood through the concept of magnetic flux lines. When currents flow clockwise or counterclockwise in both rings, the magnetic fields add up constructively between them, creating an attractive force. Conversely, if one current is reversed, the rings will repel each other, as the fields will oppose each other.
For practical applications, such as creating stable magnetic levitation systems, ensuring the correct current orientation is essential to achieve the desired attractive forces.
Wire Rings Interaction
The interaction between wire rings involves complex electromagnetic phenomena that are elegantly simplified through symmetry and mathematical reduction. When two parallel wire rings carry current, their interaction is primarily governed by their magnetic fields.
The exercise assumes that the distance d between the rings is significantly smaller than their radius a, allowing for a simplified mathematical treatment of their interactions. Through this simplification, the problem becomes manageable, providing insights into how such systems can operate.
  • The symmetry of the rings ensures that the path integrals around the rings yield straightforward calculations.
  • Uniform current distribution in such symmetric setups leads to uniform results, simplifying analysis.
  • This symmetry makes it possible to predict outcomes for systems using principles of magnetostatics and symmetries.
These interactions are not just theoretical but have practical implications in electromagnetic devices and technologies that use similar principles to guide forces and motions.

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Most popular questions from this chapter

A toroid is constructed of a magnetic material having a cross-sectional area of 2.5 cm2 and an effective length of 8 cm. There is also a short air gap of 0.25 mm length and an effective area of 2.8 cm2. An mmf of 200 At is applied to the magnetic circuit. Calculate the total flux in the toroid if the magnetic material: (a) is assumed to have infinite permeability; (b) is assumed to be linear with μr=1000;(c) is silicon steel.

A rectangular loop of wire in free space joins point A(1,0,1) to point B(3,0,1) to point C(3,0,4) to point D(1,0,4) to point A. The wire carries a current of 6 mA, flowing in the az direction from B to C. A filamentary current of 15 A flows along the entire z axis in the az direction. (a) Find F on side BC. (b) Find F on side AB. (c) Find Ftotal  on the loop.

Find the mutual inductance between two filaments forming circular rings of radii a and Δa, where Δaa. The field should be determined by approximate methods. The rings are coplanar and concentric.

A current of 6 A flows from M(2,0,5) to N(5,0,5) in a straight, solid conductor in free space. An infinite current filament lies along the z axis and carries 50 A in the az direction. Compute the vector torque on the wire segment using an origin at: (a)(0,0,5);(b)(0,0,0);(c)(3,0,0).

A toroidal core has a rectangular cross section defined by the surfaces ρ=2 cm,ρ=3 cm,z=4 cm, and z=4.5 cm. The core material has a relative permeability of 80 . If the core is wound with a coil containing 8000 turns of wire, find its inductance.

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