Chapter 5: Problem 10
A large brass washer has a \(2-\mathrm{cm}\) inside diameter, a \(5-\mathrm{cm}\) outside diameter, and is \(0.5 \mathrm{~cm}\) thick. Its conductivity is \(\sigma=1.5 \times 10^{7} \mathrm{~S} / \mathrm{m} .\) The washer is cut in half along a diameter, and a voltage is applied between the two rectangular faces of one part. The resultant electric field in the interior of the half- washer is \(\mathbf{E}=(0.5 / \rho) \mathbf{a}_{\phi} \mathrm{V} / \mathrm{m}\) in cylindrical coordinates, where the \(z\) axis is the axis of the washer. (a) What potential difference exists between the two rectangular faces? ( \(b\) ) What total current is flowing? ( \(c\) ) What is the resistance between the faces?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.