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Demonstrate the ambiguity that results when the cross product is used to find the angle between two vectors by finding the angle between \(\mathbf{A}=3 \mathbf{a}_{x}-2 \mathbf{a}_{y}+4 \mathbf{a}_{z}\) and \(\mathbf{B}=2 \mathbf{a}_{x}+\mathbf{a}_{y}-2 \mathbf{a}_{z} .\) Does this ambiguity exist when the dot product is used?

Short Answer

Expert verified
Answer: By using the dot product method, we can resolve the ambiguity in finding the angle between two vectors A and B, as the cosine function gives a unique angle within the range of [0, π].

Step by step solution

01

Calculate the cross product of A and B

The cross product of A and B can be found as: \(\mathbf{A} \times \mathbf{B} = ((-2)(-2) - (4)(1))\mathbf{a}_{x} + ((4)(2) - (3)(-2))\mathbf{a}_{y} + ((3)(1) - (2)(-2))\mathbf{a}_{z}\) Calculating the values, we get: \(\mathbf{A} \times \mathbf{B} = 4\mathbf{a}_{x} + 14\mathbf{a}_{y} + 7\mathbf{a}_{z}\)
02

Calculate the magnitudes of A, B, and AxB

To find the angle, we need the magnitudes of A, B, and AxB: \(|\mathbf{A}| = \sqrt{(3^2) + (-2^2) + (4^2)} = \sqrt{29}\) \(|\mathbf{B}| = \sqrt{(2^2) + (1^2) + (-2^2)} = \sqrt{9} = 3\) \(|\mathbf{A} \times \mathbf{B}| = \sqrt{(4^2) + (14^2) + (7^2)} = \sqrt{249}\)
03

Find the angle between A and B using cross product

Using the formula for the angle between two vectors using the cross product: \(\sin{\theta} = \frac{|\mathbf{A} \times \mathbf{B}|}{|\mathbf{A}| \cdot |\mathbf{B}|}\) \(\sin{\theta} = \frac{\sqrt{249}}{\sqrt{29} \cdot 3}\) Now, we can see the ambiguity in the cross-product method as the sine function has multiple solutions for an angle, usually leading to two possible angles. Therefore, we need to resolve this ambiguity by finding a unique angle.
04

Calculate the dot product of A and B

The dot product of A and B is given by, \(\mathbf{A} \cdot \mathbf{B} = (3)(2) + (-2)(1) + (4)(-2) = 6 - 2 - 8 = -4\)
05

Find the angle between A and B using dot product

Using the formula for the angle between two vectors using the dot product: \(\cos{\theta} = \frac{\mathbf{A} \cdot \mathbf{B}}{|\mathbf{A}| \cdot |\mathbf{B}|}\) \(\cos{\theta} = \frac{-4}{\sqrt{29} \cdot 3}\) Now, we can clearly see there's no ambiguity with the dot product. The cosine function gives a unique angle as the output, with a range of \([0, \pi]\). So, we can confirm that the ambiguity does not exist when using the dot product to find the angle between two vectors.

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Most popular questions from this chapter

Given the points \(M(0.1,-0.2,-0.1), N(-0.2,0.1,0.3)\), and \(P(0.4,0,0.1)\), find \((a)\) the vector \(\mathbf{R}_{M N} ;(b)\) the dot product \(\mathbf{R}_{M N} \cdot \mathbf{R}_{M P} ;(c)\) the scalar projection of \(\mathbf{R}_{M N}\) on \(\mathbf{R}_{M P} ;(d)\) the angle between \(\mathbf{R}_{M N}\) and \(\mathbf{R}_{M P}\).

Two unit vectors, \(\mathbf{a}_{1}\) and \(\mathbf{a}_{2}\), lie in the \(x y\) plane and pass through the origin. They make angles \(\phi_{1}\) and \(\phi_{2}\), respectively, with the \(x\) axis \((a)\) Express each vector in rectangular components; \((b)\) take the dot product and verify the trigonometric identity, \(\cos \left(\phi_{1}-\phi_{2}\right)=\cos \phi_{1} \cos \phi_{2}+\sin \phi_{1} \sin \phi_{2} ;(c)\) take the cross product and verify the trigonometric identity \(\sin \left(\phi_{2}-\phi_{1}\right)=\sin \phi_{2} \cos \phi_{1}-\cos \phi_{2} \sin \phi_{1}\)

A circle, centered at the origin with a radius of 2 units, lies in the \(x y\) plane. Determine the unit vector in rectangular components that lies in the \(x y\) plane, is tangent to the circle at \((-\sqrt{3}, 1,0)\), and is in the general direction of increasing values of \(y\).

The vector from the origin to point \(A\) is given as \((6,-2,-4)\), and the unit vector directed from the origin toward point \(B\) is \((2,-2,1) / 3\). If points \(A\) and \(B\) are ten units apart, find the coordinates of point \(B\).

Write an expression in rectangular components for the vector that extends from \(\left(x_{1}, y_{1}, z_{1}\right)\) to \(\left(x_{2}, y_{2}, z_{2}\right)\) and determine the magnitude of this vector.

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