Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Using values from Table 7.1, how many DNA molecules could be broken by the energy carried by a single electron in the beam of an old-fashioned TV tube? (These electrons were not dangerous in themselves, but they did create dangerous x rays. Later model tube TVs had shielding that absorbed x rays before they escaped and exposed viewers.)

Short Answer

Expert verified

A single electron in the beam of old-fashioned TV tube can break 40000molecules of DNA.

Step by step solution

01

Conservation of Energy

Conservation of energy:The total energy of an isolated system is always conserved. In other words, the energy neither be created nor be destroyed; it can be only transformed from one form to another.

02

Number of molecules of DNA can break by a single electron

When a single electron in the beam of an old-fashioned TV tube strikes on the molecules of DNA, the total energy of the single electron will break many molecules of DNA. Mathematically,

Eelectron=nEDNA

Here,Eelectronis the energy of single electron in the beam of old-fashioned TV tubeEelectron=4.0ร—10-15J, n is number of molecules of DNA broken, andEDNAis the energy required to break one DNA moleculeEDNA=10-19J.

The expression for the number of molecules of DNA broken is,

n=EelectronEDNA

Putting all known values,

n=4.0ร—10-15J10-19J=40000

Therefore, a single electron in the beam of anold-fashioned TV tube can break40000 molecules of DNA.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What is the difference between energy conservation and the law of conservation of energy? Give some examples of each.

Give an example of a situation in which there is a force and a displacement, but the force does no work. Explain why it does no work.

A 500-kg dragster accelerates from rest to a final speed of 110 m/s in 400 m (about a quarter of a mile) and encounters an average frictional force of 1200 N. What is its average power output in watts and horsepower if this takes 7.30 s?

Boxing gloves are padded to lessen the force of a blow.

(a) Calculate the force exerted by a boxing glove on an opponentโ€™s face, if the glove and face compress 7.50 cm during a blow in which the 7.00-kg arm and glove are brought to rest from an initial speed of 10.0 m/s.

(b) Calculate the force exerted by an identical blow in the gory old days when no gloves were used and the knuckles and face would compress only 2.00 cm.

(c) Discuss the magnitude of the force with glove on. Does it seem high enough to cause damage even though it is lower than the force with no glove?

(a) Calculate the power per square meter reaching Earthโ€™s upper atmosphere from the Sun. (Take the power output of the Sun to be4.00ร—1026W.)

(b) Part of this is absorbed and reflected by the atmosphere, so that a maximum of1.30kW/m2reaches Earthโ€™s surface. Calculate the area inkm2of solar energy collectors needed to replace an electric power plant that generates750MWif the collectors convert an average of2.00%of the maximum power into electricity. (This small conversion efficiency is due to the devices themselves, and the fact that the sun is directly overhead only briefly.) With the same assumptions, what area would be needed to meet the United Statesโ€™ energy needs(1.05ร—1020J)? Australiaโ€™s energy needs(5.4ร—1018J)? Chinaโ€™s energy needs(6.3ร—1019J)? (These energy consumption values are from 2006.)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free