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Using energy considerations, calculate the average force a 60.0-kg sprinter exerts backward on the track to accelerate from 2.00 to 8.00 m/s in a distance of 25.0 m, if he encounters a headwind that exerts an average force of 30.0 N against him.

Short Answer

Expert verified

The average force is 102N.

Step by step solution

01

Step 1: Definition of Concept

Work energy theorem: According to the work-energy theorem, the work done of the body equals the change in kinetic energy of the body.

Mathematically,

W=KEf-KEi

02

Find the work done by nonconservative force

The work done by nonconservative force is,

Wnet=Wc+Wnc (1.1)

Here,Wnetis the total work done,Wcis the work done by all conservative forces, andWncis the work done by all nonconservative forces.

The work-energy theorem states that the total amount of work done is equal to the total amount of energy used.

Wnet=ΔKE (1.2)

Here,ΔKEis the change in kinetic energy.

The work done by all conservative forces is,

Wc=Fd (1.3)

Here, F the average force exerted by the sprinter and d is the distance.

The work done by all nonconservative forces is,

Wnc=-fd (1.4)

Here, f is the opposing force.

We obtain from equations (1.1), (1.2), (1.3), and (1.4),

ΔKE=Fd-fd12mv2-12mu2=Fd-fd (1.5)

Here, m denotes mass, v denotes final velocity, and u denotes initial velocity.

03

Calculating the average force exerted by the sprinter

Rearranging equation (1.5) in order to get an expression for the average force exerted by the sprinter,

F=mv2-u22d+f

Putting 60 kg for m, 8m/s for v, 2m/s for u, 25m for d, and 30 N for f,

localid="1668678896333" F=60kg×8m/s2-2m/s22×25m+30N=102N

Therefore, the required average force exerted by the sprinter is 102 N.

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Most popular questions from this chapter

A car advertisement claims that its \(900 - {\rm{kg}}\) car accelerated from rest to \(30.0{\rm{ m}}/{\rm{s}}\) and drove \(100{\rm{ km}}\), gaining \(3.00{\rm{ km}}\) in altitude, on \(1.0{\rm{ gal}}\) of gasoline. The average force of friction including air resistance was \(700{\rm{ N}}\). Assume all values are known to three significant figures.

(a) Calculate the car’s efficiency.

(b) What is unreasonable about the result?

(c) Which premise is unreasonable, or which premises are inconsistent?

A 60.0-kgskier with an initial speed of12.0m/scoasts up a2.50mhigh rise as shown in Figure 7.40. Find her final speed at the top, given that the coefficient of friction between her skis and the snow is0.0800. (Hint: Find the distance traveled up the incline assuming a straight-line path as shown in the figure.)

Figure 7.40 The skier’s initial kinetic energy is partially used in coasting to the top of a rise.

If the efficiency of a coal-fired electrical generating plant is 35%, then what do we mean when we say that energy is a conserved quantity?

Consider the following scenario. A car for which friction is not negligible accelerates from rest down a hill, running out of gasoline after a short distance. The driver lets the car coast farther down the hill, then up and over a small crest. He then coasts down that hill into a gas station, where he brakes to a stop and fills the tank with gasoline. Identify the forms of energy the car has, and how they are changed and transferred in this series of events. (See Figure 7.34.)

Figure 7.34 A car experiencing non-negligible friction coasts down a hill, over a small crest, then downhill again, and comes to a stop at a gas station.

How much work is done by the boy pulling his sister 30.0 m in a wagon as shown in Figure 7.36? Assume no friction acts on the wagon.

Figure 7.36 The boy does work on the system of the wagon and the child when he pulls them as shown.

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