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Chapter 31: Q10 CQ (page 1147)

Is it possible for light emitted by a scintillator to be too low in frequency to be used in a photomultiplier tube? Explain.

Short Answer

Expert verified

It would be no use.

Step by step solution

01

Definition of photomultiplier tubes

Photomultiplier tubes, also known as electron multiplier tubes, are used to measure low light intensities by multiplying electrons by secondary emission. It can be used to measure the brightness of dim stars in astronomy, television camera tubes, and nuclear investigations to find and quantify tiny light flashes.

02

Step 2: Light emitted by scintillator

We know that when beam of photons strikes the metal then electrons are emitted. Only condition that matters is that the frequency of the light photons should be threshold frequency or more that.

So if the light emitted by scintillator has very low frequency, then no electrons would be emitted from the metal plate in the photomultiplier tube. Therefore it would be no help to use light of very low frequency in a photomultiplier tube.

Therefore, It would be no use.

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Most popular questions from this chapter

  1. The \(^{{\rm{210}}}\) Po source used in a physics laboratory is labelled as having an activity of \(1.0\,{\rm{\mu Ci}}\) on the date it was prepared. A student measures the radioactivity of this source with a Geiger counter and observes 1500 counts per minute. She notices that the source was prepared 120 days before her lab. What fraction of the decays is she observing with her apparatus?
  2. Identify some of the reasons that only a fraction of the ฮฑs emitted are observed by the detector.

Electron capture decay equation of 106In

ฮฑdecay producing 208Pb. The parent nuclide is in the decay series produced by 232Th, the only naturally occurring isotope of thorium.

Spontaneous radioactive decay occurs only when the decay products have less mass than the parent, and it tends to produce a daughter that is more stable than the parent. Explain how this is related to the fact that more tightly bound nuclei are more stable. (Consider the binding energy per nucleon.)

Unreasonable Results

A physicist scatters\(\gamma \)rays from a substance and sees evidence of a nucleus\(7.5 \times {10^{ - 13}}\;{\rm{m}}\)in radius. (a) Find the atomic mass of such a nucleus.

(b) What is unreasonable about this result?

(c) What is unreasonable about the assumption?
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