Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

(a) Find the charge, baryon number, strangeness, charm, and bottomness of the \({\rm{J/\psi }}\) particle from its quark composition.

(b) Do the same for the \(\Upsilon \) particle.

Short Answer

Expert verified

(a) The values for the properties of \(J/\psi \) particle is \(J/\psi \left( {B = Q = S = C = b = 0} \right)\).

(b) The values for the properties of \(\Upsilon \) particle is \(\Upsilon \left( {B = Q = S = C = b = 0} \right)\).

Step by step solution

01

Concept Introduction

A baryon is a form of composite subatomic particle in particle physics that has an odd number of valence quarks.

A quark is a basic ingredient of matter and a sort of elementary particle.

Antiquarks are the antiparticles that correspond to each flavour of quark.

02

Properties of \({\rm{J/\psi }}\) particle

(a)

Find the charge, baryon number, strangeness, charm, and bottomness of the\(J/\psi \)particle from its quark composition. Thus, from table\({\rm{33}}{\rm{.4}}\)it is obtained –

\(J/\psi = \left( {c\bar c} \right)\)

Now, from table\({\rm{33}}{\rm{.3}}\)the following can be obtained –

\({\rm{B}}\)

\({\rm{( + 1/3) + ( - 1/3) = 0}}\)

\({\rm{Q}}\)

\({\rm{( + 2/3) + ( - 2/3) = 0}}\)

\({\rm{S}}\)

\({\rm{0 + 0 = 0}}\)

\({\rm{C}}\)

\({\rm{ + 1 - 1 = 0}}\)

\({\rm{b}}\)

\({\rm{0 + 0 = 0}}\)

Therefore, the properties for\(J/\psi \)particle is obtained.

03

Properties of \(\Upsilon \) particle

(b)

Find the charge, baryon number, strangeness, charm, and bottomness of the\(\Upsilon \)particle from its quark composition. Thus, from table\({\rm{33}}{\rm{.4}}\)it is known\(\Upsilon '{\rm{s}}\)quark compositions –

\(\Upsilon = \left( {b\bar b} \right)\)

The table is as follows –

\({\rm{B}}\)

\({\rm{( + 1/3) + ( - 1/3) = 0}}\)

\({\rm{Q}}\)

\({\rm{( - 1/3) + ( + 1/3) = 0}}\)

\({\rm{S}}\)

\({\rm{0 + 0 = 0}}\)

\({\rm{C}}\)

\({\rm{0 + 0 = 0}}\)

\({\rm{b}}\)

\({\rm{ - 1 + 1 = 0}}\)

Therefore, the properties for\(\Upsilon \)particle is obtained.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free