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(a) Find the charge, baryon number, strangeness, charm, and bottomness of the \({\rm{J/\psi }}\) particle from its quark composition.

(b) Do the same for the \(\Upsilon \) particle.

Short Answer

Expert verified

(a) The values for the properties of \(J/\psi \) particle is \(J/\psi \left( {B = Q = S = C = b = 0} \right)\).

(b) The values for the properties of \(\Upsilon \) particle is \(\Upsilon \left( {B = Q = S = C = b = 0} \right)\).

Step by step solution

01

Concept Introduction

A baryon is a form of composite subatomic particle in particle physics that has an odd number of valence quarks.

A quark is a basic ingredient of matter and a sort of elementary particle.

Antiquarks are the antiparticles that correspond to each flavour of quark.

02

Properties of \({\rm{J/\psi }}\) particle

(a)

Find the charge, baryon number, strangeness, charm, and bottomness of the\(J/\psi \)particle from its quark composition. Thus, from table\({\rm{33}}{\rm{.4}}\)it is obtained –

\(J/\psi = \left( {c\bar c} \right)\)

Now, from table\({\rm{33}}{\rm{.3}}\)the following can be obtained –

\({\rm{B}}\)

\({\rm{( + 1/3) + ( - 1/3) = 0}}\)

\({\rm{Q}}\)

\({\rm{( + 2/3) + ( - 2/3) = 0}}\)

\({\rm{S}}\)

\({\rm{0 + 0 = 0}}\)

\({\rm{C}}\)

\({\rm{ + 1 - 1 = 0}}\)

\({\rm{b}}\)

\({\rm{0 + 0 = 0}}\)

Therefore, the properties for\(J/\psi \)particle is obtained.

03

Properties of \(\Upsilon \) particle

(b)

Find the charge, baryon number, strangeness, charm, and bottomness of the\(\Upsilon \)particle from its quark composition. Thus, from table\({\rm{33}}{\rm{.4}}\)it is known\(\Upsilon '{\rm{s}}\)quark compositions –

\(\Upsilon = \left( {b\bar b} \right)\)

The table is as follows –

\({\rm{B}}\)

\({\rm{( + 1/3) + ( - 1/3) = 0}}\)

\({\rm{Q}}\)

\({\rm{( - 1/3) + ( + 1/3) = 0}}\)

\({\rm{S}}\)

\({\rm{0 + 0 = 0}}\)

\({\rm{C}}\)

\({\rm{0 + 0 = 0}}\)

\({\rm{b}}\)

\({\rm{ - 1 + 1 = 0}}\)

Therefore, the properties for\(\Upsilon \)particle is obtained.

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