Question

Discuss how we know that \[{\rm{\pi }}\]-mesons\[\left( {{{\rm{\pi }}^{\rm{ + }}}{\rm{,\pi ,}}{{\rm{\pi }}^{\rm{0}}}} \right)\]) are not fundamental particles and are not the basic carriers of the strong force.

Short answer

\[{\rm{\pi }}\]-mesons \[\left( {{{\rm{\pi }}^{\rm{ + }}}{\rm{,\pi ,}}{{\rm{\pi }}^{\rm{0}}}} \right)\] are by product particle and lack quark and an anti-quark of strangeness, also these particles are unstable.

Step-by-step solution

Definition of Concept

The interplay of physical forces, such as electromagnetism and maybe even gravity, is controlled by bosons, which are sometimes referred to as force particles.

Explain how we know that \[{\rm{\pi }}\]-mesons \[\left( {{{\rm{\pi }}^{\rm{ + }}}{\rm{,\pi ,}}{{\rm{\pi }}^{\rm{0}}}} \right.\]) are not fundamental particles

These particles don't have strange quarks or antiquarks, and they're not fundamental particles because they're usually produced as a byproduct of various decays.

The strong nuclear force interacts with mesons, including\[{\rm{\pi }}\]-mesons\[\left( {{{\rm{\pi }}^{\rm{ + }}}{\rm{,\pi ,}}{{\rm{\pi }}^{\rm{0}}}} \right)\], which are made up of a quark and an anti-quark pair. However, because they contain a particle and an antiparticle to produce particles like neutrinos, photons, and electrons, they are unstable. As a result, these aren't the actual carriers of strong force.\[{{\rm{\pi }}^{\rm{ + }}}\]Mesonudand it carries a total charge of\[{\rm{2/3q + 1/3q = q}}\]. As a result, its baryon number is zero. It has a very long half-life. Despite the fact that it is made up of matter and antimatter, different flavour quarks exist, and the weak force can decay a particle by changing its flavour.

Therefore, the\[{\rm{\pi }}\]-mesons\[\left( {{{\rm{\pi }}^{\rm{ + }}}{\rm{,\pi ,}}{{\rm{\pi }}^{\rm{0}}}} \right)\]are by product particles that lack a quark and an anti-quark of strangeness, as well as being unstable.