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A patient with a pacemaker is mistakenly being scanned for an MRI image. A 10.0-cm-long section of pacemaker wire moves at a speed of 10.0 cm/s perpendicular to the MRI unit’s magnetic field and a 20.0-mV Hall voltage is induced What is the magnetic field strength?

Short Answer

Expert verified

The required magnetic field is2.00T

Step by step solution

01

Given information

The diameter of the pacemaker wire is L=10.0cm(1m100cm)=0.1m

The speed of the moving wire isv=10.00cm/s(1m100cm)=0.1m/s

Induced Hall voltage isE=20.0mV(103V1mV)=2.00×10-2V

02

Define the Hall effect

The Hall effect defines the generation of induced voltage due to the motion of charge carriers in a perpendicular applied magnetic field and can be defined as,

E=BLv…………………(1)

03

Evaluating the magnetic field

Substitute the given data in equation (1), which will result,

B=ELv=2.00×10-2V(0.1m)×(0.1m/s)=2.00T

Therefore, the required magnetic field is2.00T

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Most popular questions from this chapter


(a) A cosmic ray proton moving toward the Earth at 5.00×107m/sexperiences a magnetic force of 1.70×1016N. What is the strength of the magnetic field if there is a 45 angle between it and the proton’s velocity? (b) Is the value obtained in part (a) consistent with the known strength of the Earth’s magnetic field on its surface? Discuss.

(a) A pendulum is set up so that its bob (a thin copper disk) swings between the poles of a permanent magnet as shown in Figure 22.63. What is the magnitude and direction of the magnetic force on the bob at the lowest point in its path, if it has a positive0.250μCcharge and is released from a height of 30.0 cmabove its lowest point? The magnetic field strength is 1.50 T (b) What is the acceleration of the bob at the bottom of its swing if its mass isgrams and it is hung from a flexible string? Be certain to include a free-body diagram as part of your analysis.

Repeat Exercise 22.41 but with the loop lying flat on the ground with its current circulating counterclockwise (when viewed from above) in a location where the Earth's field is north, but at an angle 45°below the horizontal and with a strength of6.00×105T.

What is the maximum force on an aluminum rod with a 0.100-µC charge that you pass between the poles of a 1.50-T permanent magnet at a speed of 5.00 m/s? In what direction is the force?

What current is needed in the top wire in Figure 22.58(a) to produce a field of zero at the point equidistant from the wires if the currents in the bottom two wires are both 10.0 A into the page?

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