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(a) Explain how you can determine the acceleration over time from a velocity versus time graph such as the one in Figure 2.56.

(b) Based on the graph, how does acceleration change over time?

Short Answer

Expert verified

a) The slope of a velocity vs. time graph gives the value of instantaneous acceleration.

b) the acceleration increases slowly from point P to Q.

Step by step solution

01

Determination of acceleration

The acceleration of a body is calculated by the change in the velocity of the body with respect to that of time.

Here in the graph, at point P, the velocity of the object is V1, and the time taken to reach that velocity is T1.

If we take point Q in the graph, then the velocity at that point is V2, and the time is T2.

We can clearly see that the velocity is increasing from V1 to V2.

Hence it can be said that the acceleration of the body, that is, the change in the value of velocity, will also be positive.

If we want to calculate the acceleration with respect to the graph, we need to calculate the slope at points P and Q.

02

Slope of velocity versus time graph  

(a) The slope of a velocity vs. time graph gives the value of instantaneous acceleration.

b) Hence from the graph, we can see that slope of the P point is more than the slope at Q.

Here slop means the angle made by the tangent line passing through P and the x-axis.

Hence, we can say that acceleration increases.

By seeing the graph, it is clear that the acceleration increases slowly as we go from point P to Q.

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Most popular questions from this chapter

Freight trains can produce only relatively small accelerations and decelerations.

(a) What is the final velocity of a freight train that accelerates at a rate of\({\bf{0}}.{\bf{0500}}{\rm{ }}{\bf{m}}/{{\bf{s}}^{\bf{2}}}\)for\({\bf{8}}.{\bf{00}}{\rm{ }}{\bf{min}}\), starting with an initial velocity of\({\bf{4}}.{\bf{00}}{\rm{ }}{\bf{m}}/{\bf{s}}\)?

(b) If the train can slow down at a rate of\({\bf{0}}.{\bf{0500}}{\rm{ }}{\bf{m}}/{{\bf{s}}^{\bf{2}}}\), how long will it take to come to a stop from this velocity?

(c) How far will it travel in each case?

Dragsters can actually reach a top speed ofin onlyconsiderably less time than given in Example 2.10 and Example 2.11.

(a) Calculate the average acceleration for such a dragster.

(b) Find the final velocity of this dragster starting from rest and accelerating at the rate found in (a) for 402 m(a quarter mile) without using any information on time.

(c) Why is the final velocity greater than that used to find the average acceleration?

Hint: Consider whether the assumption of constant acceleration is valid for a dragster. If not, discuss whether the acceleration would be greater at the beginning or end of the run and what effect that would have on the final velocity.

Using approximate values, calculate the slope of the curve in Figure 2.62 to verify that the velocity at t = 10 s is 0.208 m/s. Assume all values are known to 3 significant figures.

Find the following for path A in Figure 2.59:

(a) The distance travelled.

(b) The magnitude of the displacement from start to finish.

(c) The displacement from start to finish.

At the end of a race, a runner decelerates from a velocity of 9.00 m/s at a rate of\({\bf{2}}\;{\bf{m/}}{{\bf{s}}^{\bf{2}}}\). (a) How far does she travel in the next 5.00 s? (b) What is her final velocity? (c) Evaluate the result. Does it make sense?

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