Chapter 2: 16 PE (page 82)
A cheetah can accelerate from rest to a speed of 30.0 m/s in 7.00 s. What is its acceleration?
Short Answer
The acceleration of the cheetah is 4.28 m/s2.
Chapter 2: 16 PE (page 82)
A cheetah can accelerate from rest to a speed of 30.0 m/s in 7.00 s. What is its acceleration?
The acceleration of the cheetah is 4.28 m/s2.
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Get started for freeFind the following for path B in Figure 2.59:
(a) The distance travelled.
(b) The magnitude of the displacement from start to finish.
(c) The displacement from start to finish.
An object that is thrown straight up falls back to Earth. This is one-dimensional motion.
(a) When is its velocity zero?
(b) Does its velocity change direction?
(c) Does the acceleration due to gravity have the same sign on the way up as on the way down?
Blood is accelerated from rest to 30.0 cm/s in a distance of 1.80 cm by the left ventricle of the heart. (a) Make a sketch of the situation. (b) List the knowns in this problem. (c) How long does the acceleration take? To solve this part, first identify the unknown, and then discuss how you chose the appropriate equation to solve for it. After choosing the equation, show your steps in solving for the unknown, checking your units. (d) Is the answer reasonable when compared with the time for a heartbeat?
(a) By taking the slope of the curve in Figure 2.60, verify that the velocity of the jet car is\({\bf{115}}{\rm{ }}{\bf{m}}/{\bf{s}}\)at\(t = {\rm{ }}{\bf{20}}{\rm{ }}{\bf{s}}\). (b) By taking the slope of the curve at any point in Figure 2.61, verify that the jet carโs acceleration is\({\bf{5}}.{\bf{0}}{\rm{ }}{\bf{m}}/{{\bf{s}}^{\bf{2}}}\).
Find the following for path A in Figure 2.59:
(a) The distance travelled.
(b) The magnitude of the displacement from start to finish.
(c) The displacement from start to finish.
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