Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

(a) Cherry-red embers in a fireplace are at 850ºC and have an exposed area of\({\bf{0}}{\bf{.200}}\;{{\bf{m}}^{\bf{2}}}\)and an emissivity of 0.980. The surrounding room has a temperature of 18.0ºC. If 50% of the radiant energy enters the room, what is the net rate of radiant heat transfer in kilowatts? (b) Does your answer support the contention that most of the heat transfer into a room by a fireplace comes from infrared radiation?

Short Answer

Expert verified

The net rate of radiant heat transfer is\({\bf{8}}{\bf{.8}}\;{\bf{kW}}\).

(b) The most of heat transfer into room by a fireplace comes from infrared radiation.

Step by step solution

01

Determination of net rate of radiant heat transfer(a)Given Data:

The area of fireplace is\(A = 0.200\;{{\rm{m}}^2}\)

The temperature of fireplace is\({T_1} = 850^\circ {\rm{C}} = 1123\;{\rm{K}}\)

The temperature of surrounding room is\({T_2} = 18^\circ {\rm{C}} = 291\;{\rm{K}}\)

The emissivity of fireplace is\(\varepsilon = 0.980\)

The percentage of radiant energy enters to room is\(x = 50\% = 0.5\)

The radiant energy transfer is calculated by using the Stefan law. This law gives the energy transfer without any medium.

The net rate of radiant heat transfer is given as:

\(Q = x\varepsilon \sigma A\left( {T_2^4 - T_1^4} \right)\)

Here, \(\sigma \) is Stefan’s constant and its value is \(5.67 \times {10^{ - 8}}\;{\rm{W}} \cdot {{\rm{m}}^{ - 2}} \cdot {{\rm{K}}^4}\)

\(\begin{aligned}{}Q &= \left( {0.5} \right)\left( {0.980} \right)\left( {5.67 \times {{10}^{ - 8}}\;{\rm{W}} \cdot {{\rm{m}}^{ - 2}} \cdot {{\rm{K}}^4}} \right)\left( {0.200\;{{\rm{m}}^2}} \right)\left( {{{\left( {1123\;{\rm{K}}} \right)}^4} - {{\left( {291\;{\rm{K}}} \right)}^4}} \right)\\Q &= 8.798 \times {10^3}\;{\rm{W}}\\Q& = \left( {8.798 \times {{10}^3}\;{\rm{W}}} \right)\left( {\frac{{1\;{\rm{kW}}}}{{{{10}^3}\;{\rm{W}}}}} \right)\\Q \approx 8.8\;{\rm{kW}}\end{aligned}\)

Therefore, the net rate of radiant heat transfer is \(8.8\;{\rm{kW}}\).

02

Proof for heat transfer by Infrared radiation

(b)

The heat transfer into room by a fireplace comes from infrared radiation because infrared radiation does not requires any medium for heat transfer.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free