Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The decay of one type of \({\rm{K}}\)-meson is cited as evidence that nature favours matter over antimatter. Since mesons are composed of a quark and an antiquark, is it surprising that they would preferentially decay to one type over another? Is this an asymmetry in nature? Is the predominance of matter over antimatter an asymmetry?

Short Answer

Expert verified

We would expect the kaon to decay into both types with equal probability, so this observation demonstrates an asymmetry in nature and contributes to efforts to explain the large asymmetry of matter's dominance over antimatter in the universe.

Step by step solution

Achieve better grades quicker with Premium

  • Unlimited AI interaction
  • Study offline
  • Say goodbye to ads
  • Export flashcards

Over 22 million students worldwide already upgrade their learning with Vaia!

01

Definition of mesons.

Generally, the matter is made up of matter but every matter contains constituent antimatter particle. The decay of one K-mesons preferentially creates matter over antimatter.

02

 Step 2: Finding whether mesons decay into one type over another?

Matter and antimatter should be equivalent pairs of opposing quantum numbers, just as a positive charge is neither better nor worse than a negative charge. This is why we expect a K-meson, especially a long-lived neutral kaon composed symmetrically of a quark-antiquark, to decay with equal probability into a "matter heavy" path and a "antimatter heavy" path. This was not noticed. With a higher probability, the -meson decays into the "matter heavy" path.

This was the first indication of a violation of CP symmetry. Because CP symmetry states that the physics should be the same in both C-symmetry (particle-antiparticle interchange) and P-symmetry (parity change, coordinate inversion) at the same time, its violation is important in attempts to explain the predominance.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose you measure the red shifts of all the images produced by gravitational lensing, such as in figure below. You find that the central image has a red shift less than the outer images, and those all have the same red shift. Discuss how this not only shows that the images are of the same object, but also implies that the red shift is not affected by taking different paths through space. Does it imply that cosmological red shifts are not caused by traveling through space (light getting tired, perhaps)?

Explain how good thermal contact with liquid nitrogen can keep objects at a temperature of\({\rm{77 K}}\)(liquid nitrogenโ€™s boiling point at atmospheric pressure).

Consider a supermassive black hole near the center of a galaxy. Calculate the radius of such an object based on its mass. You must consider how much mass is reasonable for these large objects, and which is now nearly directly observed. (Information on black holes posted on the Web by NASA and other agencies is reliable, for example.)

The critical mass density needed to just halt the expansion of the universe is approximately\({\rm{1}}{{\rm{0}}^{{\rm{ - 26}}}}{\rm{ kg/}}{{\rm{m}}^{\rm{3}}}\). (a) Convert this to\({\rm{eV/}}{{\rm{c}}^{\rm{2}}} \cdot {{\rm{m}}^{\rm{3}}}\). (b) Find the number of neutrinos per cubic meter needed to close the universe if their average mass is\({\rm{7 eV/}}{{\rm{c}}^{\rm{2}}}\)and they have negligible kinetic energies.

Another known cause of red shift in light is the source being in a high gravitational field. Discuss how this can be eliminated as the source of galactic red shifts, given that the shifts are proportional to distance and not to the size of the galaxy.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free