Question

What percentage of the final current \({\rm{I_0}}\) flows through an inductor \({\rm{L}}\) in series with a resistor\({\rm{R}}\), three-time constants after the circuit is completed?

Short answer

The\(4.98\% \)percentage of the final current\(10\)flows through an inductor \(L\) in series with a resistor \(R\), three-time constants after the circuit are completed.

Step-by-step solution

Concept Introduction

When an electric current passes through an inductor, often referred to as a coil, choke, or reactor, it stores energy in a magnetic field. An inductor is constructed from a coil of insulated wire.

Information Provided

• The current value: \(10\)

Calculating the Percentage of the Final Current

Now observe that after each period equal to the time constant, the current gets\(0.368\)times what it was before this interval. As a result, in this circumstance, all we have to do is raise this coefficient to the third power. To put it another way, if you're looking for a unique approach to express oneself,

\({0.368^3} = 4.98\% \)

Therefore, the required solution is \(4.98\% \).