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An\({\rm{emf}}\)is induced by rotating a\({\rm{1000 - }}\)turn,\({\rm{20}}{\rm{.0 cm}}\)diameter coil in the Earth’s\({\rm{5}}{\rm{.00 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}{\rm{ T}}\)magnetic field. What average\({\rm{emf}}\)is induced, given the plane of the coil is originally perpendicular to the Earth’s field and is rotated to be parallel to the field in\({\rm{10}}{\rm{.0 ms}}\)?

Short Answer

Expert verified

The average \({\rm{emf}}\) induced is obtained as \({\rm{1}}{\rm{.57}}\;{\rm{mV}}\).

Step by step solution

01

Define Electromagnetic Induction

The creation of an electromotive force across an electrical conductor in a changing magnetic field is known as electromagnetic or magnetic induction. Induction was discovered in\({\rm{1831}}\)by Michael Faraday, and it was mathematically characterized as Faraday's law of induction by James Clerk Maxwell.

02

Evaluating the average emf induced

The electromotive force is induced when a coil with the value\({\rm{N}}\)turns experiences a flux change of the value\({\rm{\Delta \Phi }}\)in time\({\rm{\Delta t}}\)is given by:

\({\rm{E = - N}}\frac{{{\rm{\Delta \Phi }}}}{{{\rm{\Delta t}}}}\)……………….(1)

The flux reaches the point zero from the maximal value under the given time, we can simply write the change in flux as:

\(\begin{aligned}{}{\rm{\Delta \Phi = 0 - BA}}\\{\rm{ = - BA}}\end{aligned}\)

The emf then will be:

\({\rm{\varepsilon = }}\frac{{{\rm{NBA}}}}{{\rm{t}}}\)……………………….(2)

Substituting the area such that:

\(\begin{aligned}{}{\rm{A = \pi }}{{\rm{R}}^{\rm{2}}}\\{\rm{ = }}\frac{{{\rm{\pi }}{{\rm{D}}^{\rm{2}}}}}{{\rm{4}}}\end{aligned}\)

Therefore the analytical result is,

\({\rm{\varepsilon = }}\frac{{{\rm{\pi NB}}{{\rm{D}}^{\rm{2}}}}}{{\rm{4}}}\)………………………(3)

The numerical value is then evaluated as:

\(\begin{aligned}{}{\rm{\varepsilon }} &= \frac{{{\rm{\pi \times 1000 \times }}\left( {{\rm{5 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}\;{\rm{T}}} \right){\rm{ \times }}{{\left( {{\rm{0}}{\rm{.2}}\;{\rm{m}}} \right)}^{\rm{2}}}}}{{\rm{4}}}\\ &= {\rm{1}}{\rm{.57\;}} \times {\rm{1}}{{\rm{0}}^{ - {\rm{3}}}}\;{\rm{V}}\left( {\frac{{1\;{\rm{mV}}}}{{{\rm{1}}{{\rm{0}}^{ - {\rm{3}}}}\;{\rm{V}}}}} \right)\\ &= {\rm{1}}{\rm{.57}}\;{\rm{mV}}\end{aligned}\)

Therefore, the average \({\rm{emf}}\) induced is obtained as \({\rm{1}}{\rm{.57}}\;{\rm{mV}}\).

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Most popular questions from this chapter

An RLC series circuit has a \(2.50\;\Omega \) resistor, a \(100\;\mu H\) inductor, and an \(80.0\;\mu F\) capacitor. (a) Find the power factor at \(f = 120\;Hz\). (b) What is the phase angle at \(120\;Hz\)? (c) What is the average power at \(120\;Hz\)? (d) Find the average power at the circuit's resonant frequency.

Your \(RL\) circuit has a characteristic time constant of \(20.0{\rm{ }}ns\), and a resistance of \(5.00{\rm{ }}M\Omega \). (a) What is the inductance of the circuit? (b) What resistance would give you a \(1.00{\rm{ }}ns\) time constant, perhaps needed for quick response in an oscilloscope?

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(a) What is the ratio of turns in the new secondary compared with the old secondary?

(b) What is the ratio of new current output to old output (at 335 kV) for the same power? (c) If the upgraded transmission lines have the same resistance, what is the ratio of new line power loss to old?

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