Chapter 19: Q21CQ (page 695)
If you wish to store a large amount of energy in a capacitor bank, would you connect capacitors in series or parallel? Explain
Short Answer
The capacitors should be connected in parallel.
Chapter 19: Q21CQ (page 695)
If you wish to store a large amount of energy in a capacitor bank, would you connect capacitors in series or parallel? Explain
The capacitors should be connected in parallel.
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Get started for freeA nervous physicist worries that the two metal shelves of his wood frame bookcase might obtain a high voltage if charged by static electricity, perhaps produced by friction.
(a) What is the capacitance of the empty shelves if they have area \(1.00 \times {10^2}\;{m^2}\) and are \(0.200\;m\) apart?
(b) What is the voltage between them if opposite charges of magnitude \(2.00nc\) are placed on them?
(c) To show that this voltage poses a small hazard, calculate the energy stored.
Construct Your Own Problem
Consider a heart defibrillator similar to that discussed in Example 19.11 . Construct a problem in which you examine the charge stored in the capacitor of a defibrillator as a function of stored energy. Among the things to be considered are the applied voltage and whether it should vary with energy to be delivered, the range of energies involved, and the capacitance of the defibrillator. You may also wish to consider the much smaller energy needed for defibrillation during open-heart surgery as a variation on this problem.
Use the characteristics of the Coulomb force to explain why capacitance should be proportional to the plate area of a capacitor. Similarly, explain why capacitance should be inversely proportional to the separation between plates.
What is the strength of the electric field between two parallel conducting plates separated by 1.00 cm and having a potential difference (voltage) between them of ?
Find the maximum potential difference between two parallel conducting plates separated by \(0.500{\rm{ }}cm\) of air, given the maximum sustainable electric field strength in air to be \(3.0 \times {10^6}{\rm{ }}V/m\).
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