Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Sketch the electric field between the two conducting plates shown in Figure 18.50, given the top plate is positive and an equal amount of negative charge is on the bottom plate. Be certain to indicate the distribution of charge on the plates.

Figure 18.50

Short Answer

Expert verified

The electric field lines between the two conducting plates are perpendicular to their surface and emerge from the positively charged plate and terminate at the negatively charged plate.

Step by step solution

01

Electric field lines

Electric field lines are the imaginary lines having no physical significance, drawn in such a way that the tangent to the line gives the direction of the electric field at that point.

02

Direction of the electric field lines between the conducting plates

The electric field lines originate from the positive charge and terminate to the negative charge.

As the top conducting plate is charged positively and the bottom conducting plate is charged negatively. Hence, the electric field is directed downwards and represented as,

Electric field lines between the conducting plates

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two point charges are brought closer together, increasing the force between them by a factor of 25. By what factor was their separation decreased?

Using the symmetry of the arrangement, determine the direction of the force on\(q\)in the figure below, given that\({q_a} = {q_b} = + 7.50{\rm{ }}\mu {\rm{C}}\)and\({q_c} = {q_d} = - 7.50{\rm{ }}\mu {\rm{C}}\). (b) Calculate the magnitude of the force on the charge\(q\), given that the square is\(10.0{\rm{ cm}}\)on a side and\(q = {\rm{2}}{\rm{.00 }}\mu {\rm{C}}\).

The classic Millikan oil drop experiment was the first to obtain an accurate measurement of the charge on an electron. In it, oil drops were suspended against the gravitational force by a vertical electric field. (See Figure 18.58.) Given the oil drop to be\(1.00{\rm{ }}\mu {\rm{m}}\)in radius and have a density of\(920{\rm{ kg}}/{{\rm{m}}^3}\): (a) Find the weight of the drop. (b) If the drop has a single excess electron, find the electric field strength needed to balance its weight.

Figure 18.58 In the Millikan oil drop experiment, small drops can be suspended in an electric field by the force exerted on a single excess electron. Classically, this experiment was used to determine the electron charge\({q_e}\)by measuring the electric field and mass of the drop.

What can you say about two charges \({q_1}\) and \({q_2}\), if the electric field one-fourth of the way from \({q_1}\) to \({q_2}\) is zero?

(a) By what factor must you change the distance between two-point charges to change the force between them by a factor of \(10\)? (b) Explain how the distance can either increase or decrease by this factor and still cause a factor of \(10\) change in the force.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free