Chapter 18: Q22CQ (page 662)
Can the belt of a Van de Graaff accelerator be a conductor? Explain.
Short Answer
No, conductor cannot be used for the construction of belt of Van de Graff generator.
Chapter 18: Q22CQ (page 662)
Can the belt of a Van de Graaff accelerator be a conductor? Explain.
No, conductor cannot be used for the construction of belt of Van de Graff generator.
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Get started for freeBare free charges do not remain stationary when close together. To illustrate this, calculate the acceleration of two isolated protons separated by\({\bf{2}}.{\bf{00}}{\rm{ }}{\bf{nm}}\)(a typical distance between gas atoms). Explicitly show how you follow the steps in the Problem-Solving Strategy for electrostatics.
Tollbooth stations on roadways and bridges usually have a piece of wire stuck in the pavement before them that will touch a car as it approaches. Why is this done?
A\(5.00{\rm{ g}}\)charged insulating ball hangs on a\(30.0{\rm{ cm}}\)long string in a uniform horizontal electric field as shown in Figure 18.56. Given the charge on the ball is\(1.00{\rm{ }}\mu {\rm{C}}\), find the strength of the field.
Figure 18.56 A horizontal electric field causes the charged ball to hang at an angle of\(8.00^\circ \).
Using the symmetry of the arrangement, determine the direction of the force on\(q\)in the figure below, given that\({q_a} = {q_b} = + 7.50{\rm{ }}\mu {\rm{C}}\)and\({q_c} = {q_d} = - 7.50{\rm{ }}\mu {\rm{C}}\). (b) Calculate the magnitude of the force on the charge\(q\), given that the square is\(10.0{\rm{ cm}}\)on a side and\(q = {\rm{2}}{\rm{.00 }}\mu {\rm{C}}\).
Sketch the electric field between the two conducting plates shown in Figure 18.50, given the top plate is positive and an equal amount of negative charge is on the bottom plate. Be certain to indicate the distribution of charge on the plates.
Figure 18.50
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