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Why can we neglect forces such as those holding a body together when we apply Newton’s second law of motion?

Short Answer

Expert verified

Internal forces acting on a body are equal and opposite in direction, so their sum must be zero. Therefore, there can be no net force from the internal forces.

Step by step solution

01

Concept of Newton’s second law of motion

Newton’s second law of motion states that the acceleration of a system is directly proportional to the net external force acting on the system and is inversely proportional to the mass of the system. Mathematically,

Fnet=ma

Herelocalid="1654165093803" Fnetis the net force,localid="1654165395003" mis the mass, andlocalid="1654165421915" ais the acceleration.

02

Explanation for neglecting the internal forces

According to Newton’s first law, the change in motion is due to the net external force. Internal forces are responsible for holding together a given body. The internal forces do not affect the motion of a body. The motion of a body is affected only by external forces.

Internal forces acting on a body are equal and opposite in direction, so their sum must be zero. Therefore, there can be no net force from the internal forces.

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Most popular questions from this chapter

Since astronauts in orbit are apparently weightless, a clever method of measuring their masses is needed to monitor their mass gains or losses to adjust diets. One way to do this is to exert a known force on an astronaut and measure the acceleration produced. Suppose a net external force of 50.0 N is exerted and the astronaut’s acceleration is measured to be 0.893 m/s2.

(a) Calculate her mass.

(b) By exerting a force on the astronaut, the vehicle in which they orbit experiences an equal and opposite force. Discuss how this would affect the measurement of the astronaut’s acceleration. Propose a method in which recoil of the vehicle is avoided.

(a) If the rocket sled shown in Figure 4.32 starts with only one rocket burning, what is the magnitude of its acceleration? Assume that the mass of the system is 2100 kg, the thrust T is 2.4×104 N, and the force of friction opposing the motion is known to be 650 N.

(b) Why is the acceleration not one-fourth of what it is with all rockets burning?

A cleaner pushes a 4.50-kg laundry cart in such a way that the net external force on it is 60.0 N. Calculate the magnitude of its acceleration.

Consider the baby being weighed in Figure 4.34.

(a) What is the mass of the child and basket if a scale reading of 55 N is observed?

(b) What is the tension T1 in the cord attaching the baby to the scale?

(c) What is the tension T2 in the cord attaching the scale to the ceiling, if the scale has a mass of 0.500 kg?

(d) Draw a sketch of the situation indicating the system of interest used to solve each part. The masses of the cords are negligible.

Figure 4.39 shows Superhero and Trusty Sidekick hanging motionless from a rope. Superhero’s mass is 90.0 kg, while Trusty Sidekick’s is 55.0 kg, and the mass of the rope is negligible.

(a) Draw a free-body diagram of the situation showing all forces acting on Superhero, Trusty Sidekick, and the rope.

(b) Find the tension in the rope above Superhero.

(c) Find the tension in the rope between Superhero and Trusty Sidekick. Indicate on your free-body diagram the system of interest used to solve each part.

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