Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Suppose you have a \(40.00 - \Omega \) galvanometer with a \(25.0 - \mu A\) sensitivity.

(a) What resistance would you put in series with it to allow it to be used as a voltmeter that has a full-scale deflection for \(0.500{\rm{ }}mV\)?

(b) What is unreasonable about this result?

(c) Which assumptions are responsible?

Short Answer

Expert verified

(a) The total resistance of the series is \(R = - 20{\rm{ }}\Omega \).

(b) Since, the resistance is negative therefore, the result is unreasonable.

(c) The assumption of small-scale deflection and high galvanometer resistance was incorrectand are responsible for unreason ability of the value obtained.

Step by step solution

01

Concept Introduction

The total flow of electrons via a wire can be used to describe the rate of electron flow. Anything that prevents current flow is referred to as "resistance." An electrical circuit needs resistance in order to transform electrical energy into light, heat, or movement.

02

Information Provided

  • Resistance in galvanometer:\(40.00 - \Omega \)
  • Sensitivity in galvanometer:\(25.0 - \mu A\)
  • Scale reading of voltmeter:\(0.500{\rm{ }}mV\)
03

Resistance in the series

a.

A \(40 - \Omega \) galvanometer having a \(25 - \mu A\) sensitivity.

Total Resistance of the voltmeter can be calculated as:

\({R_{tot}} = \frac{V}{I}\)

On substituting the values –

\(\begin{align}{}{R_{Total{\rm{ }}}} & = \frac{{0.500{\rm{ }}mV}}{{25{\rm{ }}\mu A}}\\{R_{Total{\rm{ }}}} &= \frac{{0.500 \times {{10}^{ - 3}}\;V}}{{25 \times {{10}^{ - 6}}\;A}}\\{R_{Total{\rm{ }}}} = 20{\rm{ }}\Omega \end{align}\)

As per Ohm's law, the total resistance is equal to the sum of internal resistance of galvanometer and resistance placed in series with the internal resistance. Thus, it can be written –

\({R_{Total{\rm{ }}}} = R + r\)

Now, \(r = 40{\rm{ }}\Omega \) and \({R_{Total{\rm{ }}}} = 20{\rm{ }}\Omega \).

Resistance of resistor is calculated as –

\(\begin{align}{}20{\rm{ }}\Omega & = R + 40{\rm{ }}\Omega \\R &= 20{\rm{ }}\Omega - 40{\rm{ }}\Omega \\R &= - 20{\rm{ }}\Omega \end{align}\)

Therefore, the total resistance is \(R = - 20{\rm{ }}\Omega \).

04

Unreason ability

(b)

The value for the resistance obtained is\(R = - 20{\rm{ }}\Omega \).

The value of resistance can only be positive.

Therefore, the result is unreasonable.

05

Assumptions responsible

(c)

Wrong assumption made regarding the situation was small scale deflection, large galvanometer resistance.

Therefore, small scale deflection, large galvanometer resistance are the assumptions responsible.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free