Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Semi-tractor trucks use four large\({\rm{12 - V}}\) batteries. The starter system requires \({\rm{24}}\;{\rm{V}}\), while normal operation of the truck’s other electrical components utilizes \({\rm{12}}\;{\rm{V}}\). How could the four batteries be connected to produce \({\rm{24}}\;{\rm{V}}\)? To produce \({\rm{12}}\;{\rm{V}}\)? Why is \({\rm{24}}\;{\rm{V}}\) better than \({\rm{12}}\;{\rm{V}}\) for starting the truck’s engine (a very heavy load)?

Short Answer

Expert verified

A larger voltage gives more power. Thus, \({\rm{24\;V}}\) battery is used in the starter system.

Step by step solution

01

Relation between power and voltage

Power and voltage are proportional to each other if the current is kept constant

02

Step 2: Connection of batteries to get \({\rm{24V}}\)

For creating a voltage \({\rm{12\;V}}\), connect two batteries in parallel, whereas connect two in series to generate a voltage \({\rm{24\;V}}\). It is better to put \({\rm{24\;V}}\)for starting a heavy load because a lower voltage will not be able to produce the required power as the applied resistance will be higher.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An ECG monitor must have an \(RC\) time constant less than \(1.00 \times {10^2}{\rm{ }}\mu s\) to be able to measure variations in voltage over small time intervals. (a) If the resistance of the circuit (due mostly to that of the patient’s chest) is\(1.00{\rm{ }}k\Omega \), what is the maximum capacitance of the circuit? (b) Would it be difficult in practice to limit the capacitance to less than the value found in (a)?

A12.0-Vemf automobile battery has a terminal voltage of16.0Vwhen being charged by a current of10.0A.(a) What is the battery’s internal resistance?(b) What power is dissipated inside the battery?(c) At what rate (in ºC/min) will its temperature increase if its mass is20.0kgand it has a specific heat of0.300kcal/kgx0C, assuming no heat escapes?

Apply the loop rule to loop akledcba in Figure 21.52.

(a) What is the unknownemfxin a potentiometer that balances whenRxis 10.0Ω , and balances when role="math" localid="1656393398590" Rsis 15.0Ωfor a standard 3.000-V emf? (b) The sameemfxis placed in the same potentiometer, which now balances when Rsis 15.0Ω for a standard emf of 3.100-V . At what resistanceRxwill the potentiometer balance?

Before World War II, some radios got power through a “resistance cord” that had a significant resistance. Such a resistance cord reduces the voltage to a desired level for the radio’s tubes and the like, and it saves the expense of a transformer. Explain why resistance cords become warm and waste energy when the radio is on.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free