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Two resistors, one having a resistance of 145Ω, are connected in parallel to produce a total resistance of 150Ω. (a) What is the value of the second resistance? (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?

Short Answer

Expert verified

(a)The value of the second resistance is-4350Ω.

(b)Negative value of resistance.

(c)Resistance of parallel series is in between values of separate resistors.

Step by step solution

01

Combination of parallel resistance

The resultant resistance of parallel combination resistors is given as,

1Rp=1R1+1R2

Here, Rpis the resultant resistance for parallel combination, R1and R2are the resistances of the resistors connected in parallel.


02

Calculation of the second resistance

(a)

Resistance of one of the resistors in parallel session can be calculated as:

R2=RpR1RpR=145Ω×150Ω145Ω-150Ω=-4350Ω

Therefore, the value of the second resistance isR2=-4350Ω.

03

Unreasonable about the result

(b)

This result is unreasonable because of negative value of resistance, which is not possible.

04

Inconsistence assumption

(c)

The assumptions are unreasonable or inconsistent is, resistance of parallel series is in between values of separate resistors.

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