Chapter 6: Problem 4
A ray of light travels from point \(P_{1}\) in a medium of refractive index \(n_{1}\) to \(P_{2}\) in a medium of index \(n_{2},\) by way of the point \(Q\) on the plane interface between the two media, as in Figure \(6.9 .\) Show that Fermat's principle implies that, on the actual path followed, \(Q\) lies in the same vertical plane as \(P_{1}\) and \(P_{2}\) and obeys Snell's law, that \(n_{1} \sin \theta_{1}=n_{2} \sin \theta_{2} .\) [Hints: Let the interface be the \(x z\) plane, and let \(P_{1}\) lie on the \(y\) axis at \(\left(0, h_{1}, 0\right)\) and \(P_{2}\) in the \(x, y\) plane at \(\left(x_{2},-h_{2}, 0\right) .\) Finally let \(Q=(x, 0, z)\) Calculate the time for the light to traverse the path \(P_{1} Q P_{2}\) and show that it is minimum when \(Q\) has \(z=0\) and satisfies Snell's law.]
Short Answer
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Key Concepts
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