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The potential energy of two atoms in a molecule can sometimes be approximated by the Morse function, $$U(r)=A\left[\left(e^{(R-r) / S}-1\right)^{2}-1\right]$$ where \(r\) is the distance between the two atoms and \(A, R,\) and \(S\) are positive constants with \(S \ll R .\) Sketch this function for \(0 < r < \infty\). Find the equilibrium separation \(r_{\mathrm{o}}\), at which \(U(r)\) is minimum. Now write \(r=r_{\mathrm{o}}+x\) so that \(x\) is the displacement from equilibrium, and show that, for small displacements, \(U\) has the approximate form \(U=\) const \(+\frac{1}{2} k x^{2} .\) That is, Hooke's law applies. What is the force constant \(k ?\)

Short Answer

Expert verified
The equilibrium separation is \( r_o = R \), and the force constant is \( k = \frac{2A}{S^2} \).

Step by step solution

01

Understanding the Morse Potential Function

The given function is the Morse potential: \( U(r) = A\left[\left(e^{(R-r) / S}-1\right)^{2}-1\right] \). This function describes how the potential energy \( U \) varies with the distance \( r \) between two atoms.
02

Sketching the Morse Potential

For \( 0 < r < \infty \), sketch \( U(r) \). As \( r \to 0 \), \( U(r) \to \infty \) because \( (R-r)/S \to \infty \) leads to a large exponent. As \( r \to \, \) \( \infty \), \( U(r) \to 0 \). For a minimum at some \( r_o \), \( U(r) \) starts high, drops to a minimum, then approaches zero as \( r \to \infty \).
03

Finding the Equilibrium Separation \( r_o \)

To find the minimum (equilibrium), set the derivative \( \frac{dU}{dr} = 0 \). Calculate: \[ \frac{dU}{dr} = A \cdot 2 \cdot e^{(R-r) / S}\left(e^{(R-r) / S} - 1\right) \cdot \frac{-1}{S} = 0. \] This simplifies to: \[ e^{(R-r_o)/S} = 1, \] hence, at the equilibrium separation \( r_o \), \( R = r_o \).
04

Applying Displacement from Equilibrium

Set \( r = r_o + x \), substitute into the expression: \[ U(r_o + x) = A \left( \left(e^{(R-(r_o + x)) / S} - 1\right)^2 - 1 \right). \]
05

Approximating for Small Displacements

For small \( x \), use \( e^{-(x/S)} \approx 1 - x/S + (x/S)^2/2 \) to approximate: \[ U(r_o + x) \approx A \left( \left(1 - 1 + x/S - (x/S)^2/2 \right)^2 - 1 \right). \] Simplifying gives: \[ U \approx A \left( (x/S)^2 - 1 \right). \]
06

Expressing in Hooke's Law Form

Expand the term \((x/S)^2\) and simplify: \[ U \approx -A + \frac{A}{S^2}x^2. \] This is in the form Hooke's law: \( U = \text{const} + \frac{1}{2}kx^2 \) where \( k = \frac{2A}{S^2} \).
07

Determining the Force Constant \( k \)

Thus, for Hooke's law approximation, the spring constant \( k \) is \( \frac{2A}{S^2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Separation
In the context of the Morse potential, the equilibrium separation, denoted as \( r_o \), is the point at which the potential energy \( U(r) \) is at a minimum between two atoms. Think of it as the most comfortable distance where the atoms feel least "stressed" by their interaction forces. Mathematically, this equilibrium point is found by setting the derivative of the potential energy function with respect to distance \( r \) to zero, i.e., \( \frac{dU}{dr} = 0 \). This condition reveals where the system is in a stable state with no net force acting on the atoms. In simpler terms, it's the distance where the atoms are naturally balanced without external forces pulling them closer or pushing them apart.
The equilibrium separation \( r_o \) is crucial when discussing molecular vibrations, as it serves as the reference point from which deviations are measured during vibrational motions.
Hooke's Law Approximation
When atoms are slightly displaced from their equilibrium separation \( r_o \), their interaction can often be described by Hooke's Law. This approximation simplifies the complex Morse potential to a more manageable form for small deviations. Here's how it works:
For tiny displacements \( x \) from \( r_o \), denoted as \( r = r_o + x \), we can approximate \( U(r) \) using a quadratic function similar to a spring in Hooke's Law. This results in \( U = \text{const} + \frac{1}{2} k x^2 \), where \( k \) is the "spring constant". Such an approximation holds well for many molecular vibrations, allowing physicists to analyze these movements effectively using simple harmonic motion.
  • The linear restoring force is straightforward and intuitive.
  • This approach facilitates easier mathematical handling of vibrational analyses.
Force Constant
In the context of the Morse potential, the force constant, denoted \( k \), is a measure of the stiffness of the potential energy curve around the equilibrium separation \( r_o \). It is analogous to the spring constant in classical mechanics, representing how much "force" is required to displace an atom from its equilibrium position. This is essential for understanding how strongly bonded atoms resist being stretched or compressed.
Mathematically, the force constant is derived by examining the second derivative of the potential energy function at equilibrium, which results in \( k = \frac{2A}{S^2} \). It forms a key parameter in modeling molecular vibrations, providing insights into the strength of the interaction between atoms. The higher the force constant, the more energy is required to change the distance between the atoms, indicating a stronger bond.
Potential Energy Function
The Morse potential energy function describes the energy interaction between two atoms as they move relative to each other. It is given by the equation:\[ U(r) = A \left[ \left(e^{(R-r) / S}-1\right)^{2}-1\right]\]where \( r \) is the separation between the atoms, and \( A, R, \) and \( S \) are constants with \( S \ll R \). This potential gives a more realistic approximation compared to simpler models, as it accounts for the anharmonic behavior of diatomic molecules.
The function features a well-defined minimum at \( r_o \), representing the equilibrium separation.
  • It rises steeply as \( r \) approaches zero, indicating strong repulsion when atoms are very close.
  • As \( r \) becomes very large, the potential approaches zero, suggesting that the atoms exert negligible forces on each other when far apart.
The Morse potential effectively models how molecular bonds stretch and compress during vibrational motions, capturing phenomena that simpler, idealized models like the harmonic oscillator cannot fully describe. This sensitivity to real-world molecular interactions makes it a vital tool in chemical physics.

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Most popular questions from this chapter

In order to prove the crucial formulas (5.83)?5.85) for the Fourier coefficients \(a_{n}\) and \(b_{n},\) you must first prove the following: $$\int_{-\tau / 2}^{\tau / 2} \cos (n \omega t) \cos (m \omega t) d t=\left\\{\begin{array}{ll} \tau / 2 & \text { if } m=n \neq 0 \\ 0 & \text { if } m \neq n \end{array}\right.$$ (This integral is obviously \(\tau\) if \(m=n=0 .\) ) There is an identical result with all cosines replaced by sines, and finally $$\int_{-\tau / 2}^{\tau / 2} \cos (n \omega t) \sin (m \omega t) d t=0 \quad \text { for all integers } n \text { and } m$$ where as usual \(\omega=2 \pi / \tau\). Prove these. [Hint: Use trig identities to replace \(\cos (\theta) \cos (\phi)\) by terms like \(\cos (\theta+\phi) \text { and so on. }]\)

A massless spring is hanging vertically and unloaded, from the ceiling. A mass is attached to the bottom end and released. How close to its final resting position is the mass after 1 second, given that it finally comes to rest 0.5 meters below the point of release and that the motion is critically damped?

The potential energy of a one-dimensional mass \(m\) at a distance \(r\) from the origin is $$U(r)=U_{0}\left(\frac{r}{R}+\lambda^{2} \frac{R}{r}\right)$$ for \(0 < r < \infty,\) with \(U_{\mathrm{o}}, R,\) and \(\lambda\) all positive constants. Find the equilibrium position \(r_{\mathrm{o}} .\) Let \(x\) be the distance from equilibrium and show that, for small \(x\), the PE has the form \(U=\) const \(+\frac{1}{2} k x^{2}\). What is the angular frequency of small oscillations?

Consider an underdamped oscillator (such as a mass on the end of a spring) that is released from rest at position \(x_{\mathrm{o}}\) at time \(t=0 .\) (a) Find the position \(x(t)\) at later times in the form $$x(t)=e^{-\beta t}\left[B_{1} \cos \left(\omega_{1} t\right)+B_{2} \sin \left(\omega_{1} t\right)\right]$$ That is, find \(B_{1}\) and \(B_{2}\) in terms of \(x_{\mathrm{o}}\). (b) Now show that if you let \(\beta\) approach the critical value \(\omega_{\mathrm{o}}\) your solution automatically yields the critical solution. (c) Using appropriate graphing software, plot the solution for \(0 \leq t \leq 20,\) with \(x_{\mathrm{o}}=1, \omega_{\mathrm{o}}=1,\) and \(\beta=0,0.02,0.1,0.3,\) and 1

We know that if the driving frequency \(\omega\) is varied, the maximum response \(\left(A^{2}\right)\) of a driven damped oscillator occurs at \(\omega \approx \omega_{\mathrm{o}}\) (if the natural frequency is \(\omega_{\mathrm{o}}\) and the damping constant \(\beta \ll\) \(\omega_{\mathrm{o}}\) ). Show that \(A^{2}\) is equal to half its maximum value when \(\omega \approx \omega_{\mathrm{o}} \pm \beta,\) so that the full width at half maximum is just \(2 \beta\). [Hint: Be careful with your approximations. For instance, it's fine to say \(\left.\omega+\omega_{\mathrm{o}} \approx 2 \omega_{\mathrm{o}}, \text { but you certainly mustn't say } \omega-\omega_{\mathrm{o}} \approx 0 .\right]\)

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