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A uniform spherical asteroid of radius Ro is spinning with angular velocity ωo. As the aeons go by, it picks up more matter until its radius is R. Assuming that its density remains the same and that the additional matter was originally at rest relative to the asteroid (anyway on average), find the asteroid's new angular velocity. (You know from elementary physics that the moment of inertia is 25MR2.) What is the final angular velocity if the radius doubles?

Short Answer

Expert verified
When the radius doubles, the angular velocity becomes ωo4.

Step by step solution

01

Identify Initial Conditions

We begin with an asteroid of initial radius Ro and angular velocity ωo. The density is constant, which implies that its mass Mo is proportional to the volume, i.e., Mo=ρ43πRo3 for some constant density ρ.
02

Understand Moment of Inertia

The moment of inertia I of a sphere with mass M and radius R is given by I=25MR2. We will use this formula to find the initial and final moments of inertia, Io and I, respectively.
03

Apply Conservation of Angular Momentum

Angular momentum L is conserved. Initially, Lo=Ioωo=25MoRo2ωo. After acquiring more mass, the final mass M and therefore the new angular momentum is L=Iω=25MR2ω. Thus, 25MoRo2ωo=25MR2ω.
04

Solve for Final Angular Velocity

Since M remains proportional to the asteroid's volume with constant density, M=ρ43πR3. Therefore, Mo=ρ43πRo3=MRo3R3. Substitute Mo in the conservation equation to obtain: ω=ωo(RoR)2.
05

Evaluate for Given Problem Condition

Given that the radius doubles, R=2Ro. Substitute into ω=ωo(RoR)2 to find ω=ωo(Ro2Ro)2=ωo14. Thus, when the radius doubles, the final angular velocity is ω=ωo4.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Angular Momentum
The principle of conservation of angular momentum is a fundamental concept in physics. It states that if no external torque acts on a system, the total angular momentum of the system remains constant. Angular momentum is the rotational equivalent of linear momentum and is given by the product of an object's moment of inertia and its angular velocity. In mathematical terms, this is expressed as L=Iω. For the asteroid scenario, since there are no external torques acting on it, the initial angular momentum, Lo, must equal the final angular momentum, L. This allows us to set up an equation that we can solve for the asteroid's new angular velocity after it has accumulated more mass. This relationship is crucial to solving problems that involve rotational dynamics without external torques.
Moment of Inertia
Moment of inertia is a key concept when dealing with rotational dynamics. It measures an object's resistance to changes in its rotation and depends on both its mass and how that mass is distributed with respect to the axis of rotation. For a solid sphere, the moment of inertia I is given by 25MR2, where M is the mass and R is the radius. In the asteroid problem, knowing how to calculate the moment of inertia is vital for determining both the initial and the new angular momentum of the asteroid. By understanding how moment of inertia changes with mass and radius, you can apply this knowledge to find the asteroid's changed rotational state after it accretes more mass.
Angular Velocity
Angular velocity represents how fast an object rotates or spins and is typically measured in radians per second. It is a vector quantity, which means it has both magnitude and direction. In the question involving the spherical asteroid, the initial angular velocity, ωo, is provided, and the task is to find the final angular velocity after the asteroid acquires more mass and its radius increases. With the principle of conservation of angular momentum, the relationship between initial and final angular velocity can be expressed mathematically, showing how changes in the asteroid's properties affect its rotational speed. This concept is particularly important when considering rotational motion in a vacuum or space, where external influences are minimal.
Spherical Asteroid
A spherical asteroid provides an ideal example of symmetry in physics, simplifying the analysis of its properties. Assuming the asteroid remains spherical as it gains mass means its density stays uniform, simplifying the calculation of its mass increase. This fact is important because the moment of inertia formula 25MR2 and any related calculations depend on the object's shape. For any changes in the asteroid, consistent logic is applied: by keeping the shape uniform, we can consistently predict how mass—and thereby volume—increase affects rotational dynamics. This hypothetical scenario helps students understand the systematic approach to solving real-world physics problems involving celestial bodies.
Physics Problem Solving
When tackling physics problems, like the one involving the asteroid, a structured and strategic approach is essential. Here’s a simple guide:
  • Identify what you know and what you need to find out—list known quantities such as initial angular velocity, radius, and constraints like constant density.
  • Understand the core concepts that apply—use your understanding of conservation of angular momentum, moment of inertia, and angular velocity.
  • Set up relevant equations based on these principles—like equating the initial and final angular momentum to find the new angular velocity.
  • Solve systematically, step by step, and check units at each stage to avoid mistakes.
  • Review the solution to ensure it makes sense physically—consider if, for instance, an increase in mass should logically slow down the rotation as predicted.
Solid problem-solving strategies not only help you solve individual exercises but also develop skills to tackle more complex physics challenges in the future.

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Most popular questions from this chapter

To illustrate the use of a multistage rocket consider the following: (a) A certain rocket carries 60% of its initial mass as fuel. (Thatis, the mass of fuel is 0.6mo.) What is the rocket's final speed, accelerating from rest in free space, if it burns all its fuel in a single stage? Express your answer as a multiple of vex. (b) Suppose instead it burns the fuel in two stages as follows: In the first stage it burns a mass 0.3mo of fuel. It then jettisons the first-stage fuel tank, which has a mass of 0.1mo, and then burns the remaining 0.3mo of fuel. Find the final speed in this case, assuming the same value of vex throughout, and compare.

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A rocket (initial mass mo ) needs to use its engines to hover stationary, just above the ground. (a) If it can afford to burn no more than a mass λmo of its fuel, for how long can it hover? [Hint: Write down the condition that the thrust just balance the force of gravity. You can integrate the resulting equation by separating the variables t and m. Take vex  to be constant.] (b) If vex3000m/s and λ10%, for how long could the rocket hover just above the earth's surface?

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Consider a gun of mass M (when unloaded) that fires a shell of mass m with muzzle speed v. (That is, the shell's speed relative to the gun is v.) Assuming that the gun is completely free to recoil (no external forces on gun or shell), use conservation of momentum to show that the shell's speed relative to the ground is v/(1+m/M).

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