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Prove that for any two matrices \(A\) and \(B\), where \(A\) has as many columns as \(B\) has rows, the transpose of \(A B\) satisfies \((A B)=\tilde{B} \tilde{A}\)

Short Answer

Expert verified
The transpose of a matrix product \((AB)^T\) equals \(B^T A^T\).

Step by step solution

01

Understand the Problem

We need to show that the transpose of the product of two matrices, \(A\) and \(B\), is equal to the product of their transposes in reverse order, i.e., \((AB)^T = B^T A^T\).
02

Definition of Matrix Transpose

Recall that the transpose of a matrix \(C\), denoted \(C^T\), is formed by swapping its rows with columns. Therefore, if \(C = AB\), then \(C^T\) will have its \((i,j)\)-th element equal to the \((j,i)\)-th element of \(C\).
03

Expression for Matrix Product

The element \((i, j)\) of the matrix product \(AB\) is given by \((AB)_{ij} = \sum_{k} a_{ik} b_{kj}\).
04

Transpose of Product \((AB)^T\)

The element \((j, i)\) of \((AB)^T\) is \((AB)_{ij}\)'s transpose, which yields \((AB)^T_{ji} = (AB)_{ij} = \sum_{k} a_{ik} b_{kj}\).
05

Expression for Transposed Product \(B^T A^T\)

The element \((j, i)\) of \(B^T A^T\) is \(\sum_{k} (B^T)_{jk} (A^T)_{ki} = \sum_{k} b_{kj} a_{ik}\).
06

Comparing Transpose Expressions

Compare \( (AB)^T_{ji} = \sum_{k} a_{ik} b_{kj} \) and \( (B^T A^T)_{ji} = \sum_{k} b_{kj} a_{ik} \). They are identical, showing that \( (AB)^T = B^T A^T \).
07

Conclusion

Since both expressions for \((AB)^T\) and \(B^T A^T\) are equal for any matrix element \((j, i)\), we conclude that \((AB)^T = B^T A^T\), proving the statement.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Multiplication
Matrix multiplication is a fundamental operation in linear algebra, allowing us to combine matrices in meaningful ways. It involves combining rows of the first matrix with columns of the second matrix. To multiply two matrices, you need to satisfy the condition where the number of columns in the first matrix equals the number of rows in the second matrix.

When multiplying matrices, every element of the resulting matrix is computed through a dot product. This means, for each element in the resulting matrix, you take the corresponding row from the first matrix and the corresponding column from the second matrix, multiply them element-wise, and sum up the results.
  • For example, if you are multiplying a 2x3 matrix A by a 3x2 matrix B, the resulting matrix will be a 2x2 matrix.
  • The element in the first row and first column of the resulting matrix is determined by multiplying the first row of A by the first column of B.
Understanding matrix multiplication is crucial because it is the groundwork for many other operations in linear algebra, such as finding the determinant, inverse, and solving systems of equations.
Linear Algebra
Linear algebra is the branch of mathematics concerning linear equations, linear functions, and their representations in vector spaces and matrices. It provides an essential framework for solving various mathematical problems and is heavily used in fields like computer science, physics, and engineering.

Several key concepts are part of linear algebra:
  • Vectors and Vector Spaces: A vector is a quantity defined by both magnitude and direction, and a vector space is a collection of vectors.
  • Matrices and Matrix Operations: Matrices represent linear transformations and can be added, subtracted, and multiplied.
  • Determinants and Inverses: The determinant provides information about the matrix's properties, and the inverse helps in solving matrix equations.
Linear algebra's power lies in its ability to abstract and simplify complex problems by allowing the use of matrix operations and transformations.
Mathematical Proof
Mathematical proofs are logical arguments that verify the truth of mathematical statements. Proofs are the bedrock of mathematics, ensuring that the results we use and trust are correct. In the context of matrix theory, you often need to prove properties and theorems that apply to matrices and operations like transposition and multiplication.

Consider the proof task: showing that the transpose of a matrix product equals the product of transposes in reverse order, i.e., \((AB)^T = B^T A^T\). This involves several steps:
  • Understanding the definitions and properties of matrix transpose and multiplication.
  • Deriving general expressions for both \((AB)^T\) and \(B^T A^T\).
  • Logical comparison of expressions to show equivalence.
Good proofs check every logical step, ensuring that the derived expressions truly match, validating the theorem's claims beyond simple intuition.

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Most popular questions from this chapter

As an observer moves through space with position \(\mathbf{x}(t),\) the four- vector \((\mathbf{x}(t), c t)\) traces a path through space-time called the observer's world line. Consider two events that occur at points \(P\) and \(Q\) in space-time. Show that if, as measured by the observer, the two events occur at the same time \(t,\) then the line joining \(P\) and \(Q\) is orthogonal to the observer's world line at the time \(t\); that is, \(\left(x_{P}-x_{Q}\right) \cdot d x=0,\) where \(d x\) joins two neighboring points on the world line at times \(t\) and \(t+d t\).

(a) What is a mass of \(1 \mathrm{MeV} / c^{2}\) in kilograms? ( \(\mathbf{b}\) ) What is a momentum of \(1 \mathrm{MeV} / c\) in \(\mathrm{kg} \cdot \mathrm{m} / \mathrm{s} ?\)

Since the four-velocity \(u=\gamma(\mathbf{v}, c)\) is a four-vector its transformation properties are simple. Write down the standard Lorentz boost for all four components of \(u\). Use these to deduce the relativistic velocity- addition formula for v.

Consider two events that occur simultaneously at \(t=0\) in frame \(\mathcal{S},\) both on the \(x\) axis at \(x=0\) and \(x=a\). (a) Find the times of the two events as measured in a frame \(\mathcal{S}^{\prime}\) traveling in the positive direction along the \(x\) axis with speed \(V\). (b) Do the same for a second frame \(\mathcal{S}^{\prime \prime}\) traveling at speed \(V\) but in the negative direction along the \(x\) axis. Comment on the time ordering of the two events as seen in the three different frames. This startling result is discussed further in Section 15.10 .

Prove that if \(T\) and \(a\) are respectively a four-tensor and a four-vector, then \(b=T \cdot a=T G a\) is a four-vector; that is, it transforms according to the rule \(b^{\prime}=\Lambda b\)

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